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boyakko [2]
3 years ago
10

Uniform supply accepted a 4800 90 day 10%

Mathematics
1 answer:
nika2105 [10]3 years ago
7 0

sorry I just need the extra points

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How can you graph rational functions including zero an how can you graph rational functions including zero and asymptotes
Anestetic [448]

Use a graphing calculator to graph. Then, you can add the zero by finding where it intercepts the x- axis. Then, the asymptotes are lines that the rational function doesn't touch. Like this. The asymptotes are the Green and blue lines, the zero is at the origin.

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PLEASE HELP 30 POINTS ! !
sukhopar [10]

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12

Step-by-step explanation:

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10, 13, 19, 28, 40 repeating patterns
photoshop1234 [79]
Each number goes up by 3. 13-10=6, 19-13=9, 40-28=12, etc. The next number would be 40+15=55
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3 years ago
The car travelled at the constant speed of 50.5 mph for 3 hours.<br> How far did the car travelled?
german

151.5 miles

Step-by-step explanation:

50.5 × 3 = 151.5

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HELP ASAP!! Identify the matrix transformation of ΔPQR, which has coordinates P(−5, −2),Q(−6, −3), and R(−2, −3), for reflection
podryga [215]

Answer:

Matrix transformation = \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]

Vertices of the new image: P'= (5,-2), Q'= (6,-3), R'= (2,-3)

Step-by-step explanation:

Transformation by reflection will produce a new congruent object in different coordinate. Reflection to y-axis made by multiplying the x coordinate with -1 and keep the y coordinate unchanged. The matrix transformation for reflection across y-axis should be: \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right].

To find the coordinate of the vertices after transformation, you have to multiply the vertices with the matrix. The calculation of the each vertice will be:

P'= \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right] \left[\begin{array}{ccc}-5\\-2\end{array}\right]= (5,-2)

Q'= \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right] \left[\begin{array}{ccc}-6\\-3\end{array}\right]= (6,-3)

R'= \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right] \left[\begin{array}{ccc}-2\\-3\end{array}\right]= (2,-3)

3 0
3 years ago
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