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gogolik [260]
2 years ago
7

A teacher surveyed her class after they had taken a vocabulary test. Eighteen of the students claimed they had studied at least

one hour for the test. The remaining twelve students admitted that they had not studied for the test at all. The test results (expressed as a percent) for the two groups are shown below. Studied: 88, 100, 94, 79, 92, 100, 95, 83, 89, 99, 100, 91, 89, 95, 100, 93, 96, 84 Did Not Study: 82, 72, 45, 91, 58, 83, 65, 87, 90, 77, 73, 89 1. Calculate the range and interquartile range for each set of data. 2. Using complete sentences, compare the data sets based on your results in part A.
Mathematics
1 answer:
raketka [301]2 years ago
7 0

Answer:

C and E are correct

Step-by-step explanation:

We have to calculate mean , median and mode for both groups first:

So,

For the group that studied:

Mean = 92.61

Median=93.5

Mode = 100

For the group that didn't studied:

Mean = 76

Median = 79.5

Mode = No Mode

So,

For statement A:

the difference between means is: 92.61-76=16.61

So the statement is incorrect.

B: There is no mode of the group that studied.

This is not true as the group has a mode of 100

C.The median of the group that did not study is less than 80.

This is true as the median of the group that didn't study is 79.5.

D. The median of the group that studied is over 95

False as the median is less than 95.

E. In general, those students that studied scored much higher than those students that did not study.​

As the mean of the group that studied is much more than the group that didn't study so the statement is true .

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