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OLEGan [10]
3 years ago
15

2) Find the area. * 7 points 12 cm 2 cm 4 cm 6 cm 24 O 12 36 48

Mathematics
1 answer:
AleksAgata [21]3 years ago
5 0

Answer:

36cm

first we extend one of the half lines.

now we have 2 rectangles with sides

  • 6cm and 4cm
  • and
  • 2cm and 6cm

using area of rect formula we find the area of both the rects separately and then add them

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The formula of a midpoint of PQ:

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1. What is the area of this polygon?
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Answer:

Part 1) The area of the polygon is 42\ units^{2}

Part 2) The area of the polygon is 43.5\ units^{2}

Step-by-step explanation:

Part 1) we know that

The area of the figure is equal to the area of rectangle GPST plus the area of triangle PES

Observing the graph

<u>Find the area of rectangle</u>

A=bh=5*7=35\ units^{2}

<u>Find the area of triangle</u>

A=(1/2)bh=(1/2)*7*2=7\ units^{2}

The area of the figure is equal to

35\ units^{2}+7\ units^{2}=42\ units^{2}

see the attached figure N 1 to better understand the problem

Part 2) we know that

The area of the figure is equal to the area of two triangles  plus the area of a trapezoid

Observing the graph

<u>Find the area of triangle 1</u>

A=(1/2)bh=(1/2)*3*2=3\ units^{2}

<u>Find the area of triangle 2</u>

A=(1/2)bh=(1/2)*5*1=2.5\ units^{2}

<u>Find the area of trapezoid</u>

A=(1/2)(b1+b2)h=(1/2)*(11+8)*4=38\ units^{2}

The area of the figure is equal to

3\ units^{2}+2.5\ units^{2}+38\ units^{2}=43.5\ units^{2}

see the attached figure N 2 to better understand the problem

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