Answer and Step-by-step explanation:
(a) Given that x and y is even, we want to prove that xy is also even.
For x and y to be even, x and y have to be a multiple of 2. Let x = 2k and y = 2p where k and p are real numbers. xy = 2k x 2p = 4kp = 2(2kp). The product is a multiple of 2, this means the number is also even. Hence xy is even when x and y are even.
(b) in reality, if an odd number multiplies and odd number, the result is also an odd number. Therefore, the question is wrong. I assume they wanted to ask for the proof that the product is also odd. If that's the case, then this is the proof:
Given that x and y are odd, we want to prove that xy is odd. For x and y to be odd, they have to be multiples of 2 with 1 added to it. Therefore, suppose x = 2k + 1 and y = 2p + 1 then xy = (2k + 1)(2p + 1) = 4kp + 2k + 2p + 1 = 2(kp + k + p) + 1. Let kp + k + p = q, then we have 2q + 1 which is also odd.
(c) Given that x is odd we want to prove that 3x is also odd. Firstly, we've proven above that xy is odd if x and y are odd. 3 is an odd number and we are told that x is odd. Therefore it follows from the second proof that 3x is also odd.
as you already know, we start off by doing a quick switcheroo on the variables, and then we solve for y to get the inverse,
and if you run a vertical line test on that expression, you'll find that it doesn't pass it, meaning is not a function.
15 miles and 3/4th hope this helps
Answer:
C ≤ 2
Step-by-step explanation:
Given that :
Clayton is at most 2 meters above sea level ;
Let Clayton = C
Clayton's distance can be represented by the inequality :
2 meters above sea level is positive, +2
At most 2 meters above sea level means, Clayton could be anywhere between + 2 metwrs but not more than 2 meters
Hence, Clayton's distance can be represented by the inequality :
C ≤ 2
Answer:
like terms: (3n,-n),(7,-3)
Step-by-step explanation:
