<h3>
Answer: C) -1/2</h3>
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Explanation:
We'll apply the derivative to get
g(x) = 4x^3 + 3x^2
g ' (x) = 3*4x^2 + 2*3x
g ' (x) = 12x^2 + 6x
Set that equal to 0 and solve for x. We do this to find where the horizontal tangents are located.
g ' (x) = 0
12x^2 + 6x = 0
6x(2x + 1) = 0
6x = 0 or 2x+1 = 0
x = 0 or x = -1/2
Adding those two said solutions yields us the final answer choice C
Answer:
A quadratic equation is some thing like
(x+2)^2
or
(x+2)(x+5)
In order to solve them, the most basic method is the FOIL method
F-First
O-Outside
I-Inner
L-Last
So for example
(x+2)^2
Which is basically
(x+2)(x+2)
So the first is the 2 Xs
(x+2)(x+2)
x*x=x^2
The outer is the x and the 2,
(x+2)(x+2)
2*x=2x
Now the Inner which is the 2 and the x
(x+2)(x+2)
2*x=2x
And finally the last which is the 2 and the second 2
(x+2)(x+2)
2*2=4
Now add them all up
X^2+2x+2x+4
Combine like terms
x^2+4x+4
There you have it
Do the same with every other quadratic equation
