The temp was 4 because of him doing temp
Given one to one f(6)=3, f'(6)=5, find tangent line to y=f⁻¹(x) at (3,6)
OK, we know
f⁻¹(3)=6
The inverse function is the reflection in y=x. So slopes, i.e. the derivative will be the reciprocal. We know the derivative of f at 6 is 5, so the derivative of f⁻¹ at y=6 is 1/5, which corresponds to x=3.
f⁻¹ ' (3) = 1/5
That slope through (3,6) is the tangent line we seek:
y - 6 = (1/5) (x-3)
That's the tangent line.
y = x/5 + 27/5
9514 1404 393
Answer:
up: (-3, 5); down: (-3, -3); right: (1, -2); left: (-6, -2)
Step-by-step explanation:
As you know, the coordinates of a given point tell you the distance ...
(right, up)
So, a displacement 7 units up adds 7 to the second coordinate value:
A(-3, -2) ⇒ A'(-3, -2+7) = A'(-3, 5) . . . . 7 units up
Likewise, 1 unit down subtracts 1 unit from the second coordinate value:
A(-3, -2) ⇒ A'(-3, -3) . . . . 1 unit down
__
Similarly, left-right changes affect only the first coordinate. Displacements right are added; displacements left are subtracted.
A(-3, -2) ⇒ A'(-3+4, -2) = A'(1, -2) . . . . 4 units right
A(-3, -2) ⇒ A'(-6, -2) . . . . 3 units left
Answer:
+1 on top +2 on bottom
Step-by-step explanation:
Answer:
a]2.3 hrs
b]3.6hrs
Step-by-step explanation:
4hrs = 12 miles
x = 7miles
4 x 7=28/12=2.3
4 x 11=44/12=3.6hrs
