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marusya05 [52]
3 years ago
6

;) yeah Imma just cheat my way through school you guys help a lot

Mathematics
1 answer:
amid [387]3 years ago
6 0

Answer:

Thanks you too

Step-by-step explanation:

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Please I need 1,2, and 4
Virty [35]

Answer:what grade are you in?

Step-by-step explanation:

7 0
3 years ago
Can 8x be added to 56? Why or why not?<br> Use rich text?
Vladimir [108]

Answer:

see below

Step-by-step explanation:

8x and 56 are not like terms

x is a variable and 56 is a constant

8x can be added to 56 but they cannot be combined together into one term

8x+56 cannot be combined because they are not like terms

7 0
3 years ago
I. For any uniform probability distribution, the mean and standard deviation can be computed by knowing the maximum and minimum
masha68 [24]

Answer: I. True

II. True

III. True

Step-by-step explanation:

Uniform probability distributions, this are probability distributions which have equally likely outcomes. There are two known types of uniform distributions:

1. discrete

2. continuous.

In the first type of distribution, each outcome is discrete. In a continuous distribution, outcomes are continuous this means they are usually infinite.

6 0
3 years ago
Does anyone know the answer?
laila [671]

Answer:

a. θ = 30°

b. μ = √3 / 15 ≈ 0.115

Step-by-step explanation:

Draw a free body diagram for each scenario (see attached figure).  The body has four forces acting on it:

  • Weight pulling down
  • Normal force perpendicular to the incline
  • Applied force parallel up the incline
  • Friction force parallel to the incline

Remember that friction opposes the direction of motion.  So when the body is sliding up, friction points down the incline.  And when the body is sliding down, friction points up the incline.

Now apply Newton's second law to each scenario, first in the normal direction, then in the parallel direction.

For sliding up, sum of the forces normal to the incline:

∑F = ma

N − mg cos θ = 0

N = mg cos θ

Sum of the forces parallel to the incline:

∑F = ma

P₁ − f − mg sin θ = 0

P₁ − Nμ − mg sin θ = 0

Substituting the expression for normal force:

P₁ − mgμ cos θ − mg sin θ = 0

Now for sliding down, sum of the forces normal to the incline:

∑F = ma

N − mg cos θ = 0

N = mg cos θ

And sum of the forces parallel to the incline:

∑F = ma

P₂ + f − mg sin θ = 0

P₂ + Nμ − mg sin θ = 0

Substituting the expression for normal force:

P₂ + mgμ cos θ − mg sin θ = 0

We know that P₁ = 6 kg.wt, P₂ = 4 kg.wt, and mg = 10 kg.wt.

So we have two equations and two unknowns (μ and θ):

P₁ − mgμ cos θ − mg sin θ = 0

P₂ + mgμ cos θ − mg sin θ = 0

Let's start by adding the equations together:

P₁ + P₂ − 2 mg sin θ = 0

P₁ + P₂ = 2 mg sin θ

sin θ = (P₁ + P₂) / (2 mg)

Plugging in the values:

sin θ = (6 + 4) / (2 × 10)

sin θ = 1/2

θ = 30°

Now we can plug this into either equation and find μ.

P₁ − mgμ cos θ − mg sin θ = 0

6 − (10 cos 30°) μ − 10 sin 30° = 0

6 − 5√3 μ − 5 = 0

1 = 5√3 μ

μ = √3 / 15

μ ≈ 0.115

6 0
3 years ago
Select the correct answer(s) from the given options:
Olegator [25]

Answer:

A

Step-by-step explanation:

All you have to is multiply 5x20 = 100 and 5 x 10 = 50 Then add and you get 150.

5 0
3 years ago
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