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saw5 [17]
4 years ago
12

Hello! Searching for A smart person ‍

Mathematics
2 answers:
adell [148]4 years ago
6 0
The answer is 2 :)
9/4-1/4
9-1=8
4
8/4
2
iVinArrow [24]4 years ago
4 0
10.

3 3/4 is 3x4+4= 15

1 1/4 is 1x4+1=5

subtract 5 from 15 you get 10 

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Solve the quadratic function by completing the square. What are the missing pieces in the steps?
Thepotemich [5.8K]

Answer:23x

Step-by-step explanation:

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3 0
4 years ago
Prove that tan22° + tan23° + tan22°. tan23° = 1 ​
postnew [5]

Answer:

Hope you got it....

Step-by-step explanation:

1=tan45∘

1=tan(22∘+23∘)

1=tan22∘+tan23∘1−tan22∘tan23∘

1−tan22∘tan23∘=tan22∘+tan23∘

1=tan22∘+tan23∘+tan22∘tan23∘

It will be the same for any two angles that add up to 45∘.

7 0
3 years ago
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What is the prime factorization of 56?
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2x2x2x7 is the correct answer
7 0
3 years ago
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There are 2 seats on the left side on each row and 3 seats on the right side there are 90 seats on the right side of the plane h
arsen [322]

Answer:

Total number of seats on plane is 150 seats.

Step-by-step explanation:

Number of seats on left side = 2 in each row

Number of seats on right side = 3 in each row

Total number of seats on right side = 90

Number of rows = total number of seats on right side/ number of seats on right in each row

Number of rows = 90 / 3 = 30 rows

So, total number of seats on left side = 30 * 2 = 60 seats

Total number of seats = total seats on right side + total seats on left side

Total number of seat = 90+ 60 = 150 seats

Hence total number of seats on plane is 150 seats.

6 0
3 years ago
An airplane leaves an airport and flies due west 150 miles and then 170 miles in the direction S 49.17°W. How far is the plane f
Ganezh [65]

Answer:

299.99 miles

Step-by-step explanation:

Since the plane traveled due west,

The total angle is 49.17 + 90

Represent that with θ

θ = 49.17 + 90

θ = 139.17.

Represent the sides as

A = 170

B = 150

C = unknown

Since, θ is opposite side C, side C can be calculated using cosine formula as;

C² = A² + B² - 2ABCosθ

Substitute values for A, B and θ

C² = 150² + 170² - 2 * 150 * 170 * Cos 139.17

C² = 22500 + 28900 - 51000 * Cos 139.17

C² = 51400 - 51000 (−0.7567)

C² = 51400 + 38,591.7

C² = 89,991.7

Take Square Root of both sides

C = 299.9861663477167

C = 299.99 miles (Approximated)

Hence, the distance between the plane and the airport is 299.99 miles

8 0
4 years ago
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