Answer:
Solution is invalid
Step-by-step explanation:
Let the time when they will have the same water content be x hours
At x hours;
For the first tank, the content will be;
50 + 10x
For the second;
29 + 3x
Equating both, will give us x
29 + 3x = 50 + 10x
We will get x as a negative number here
Since number of hours can not be negative, the solution is invalid
Here BD is perpendicular bisector
So
Apply Pythagorean theorem
Answer:
Step-by-step explanation:
B=3x-2
C=12x+2
D=B=3x-2 (Vertically opposite angles)
A=?
Now; we know, A+B+C+D=360 deg.
=>A=360-(B+C+D)
=360-(3x-2+12x+2+3x-2)
=360-(18x-2) ----[1]
B+C=180 deg. (linear pair)
=> 3x-2+12x+2=180
=> 15x=180
=> x=180/15
=12 ---[2]
subsitute [2] in [1];
=> A= 360-(18x-2)
= 360-(18*12-2)
= 360-(116-2)
= 360-214
= 146 deg.
So, the correct answer is (D).
Hope the answer is useful.
4 tenths and 2 hundredths is written .42
2 tenths and 4 hundreds is written .24
.42 is greater than .24
.42 > .24
Hope this helps.
Answer:
Step-by-step explanation:
The genral form of a complex number in rectangular plane is expressed as z = x+iy
In polar coordinate, z =rcos ∅+irsin∅ where;
r is the modulus = √x²+y²
∅ is teh argument = arctan y/x
Given thr complex number z = 6+6√(3)i
r = √6²+(6√3)²
r = √36+108
r = √144
r = 12
∅ = arctan 6√3/6
∅ = arctan √3
∅ = 60°
In polar form, z = 12(cos60°+isin60°)
z = 12(cosπ/3+isinπ/3)
To get the fourth root of the equation, we will use the de moivres theorem; zⁿ = rⁿ(cosn∅+isinn∅)
z^1/4 = 12^1/4(cosπ/12+isinπ/12)
When n = 1;
z1 = 12^1/4(cosπ/3+isinn/3)
z1 = 12^1/4cis(π/3)
when n = 2;
z2 = 12^1/4(cos2π/3+isin2π/3)
z2 = 12^1/4cis(2π/3)
when n = 3;
z2 = 12^1/4(cosπ+isinπ)
z2 = 12^1/4cis(π)
when n = 4;
z2 = 12^1/4(cos4π/3+isin4π/3)
z2 = 12^1/4cis(4π/3)
