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oksano4ka [1.4K]
3 years ago
14

An airplane leaves an airport and flies due west 150 miles and then 170 miles in the direction S 49.17°W. How far is the plane f

rom the airport (round to the nearest mile)? (2 points) PLEASE HELP ASAP 30 POINTS!!!!!!! need full explanation and work

Mathematics
1 answer:
Ganezh [65]3 years ago
8 0

Answer:

299.99 miles

Step-by-step explanation:

Since the plane traveled due west,

The total angle is 49.17 + 90

Represent that with θ

θ = 49.17 + 90

θ = 139.17.

Represent the sides as

A = 170

B = 150

C = unknown

Since, θ is opposite side C, side C can be calculated using cosine formula as;

C² = A² + B² - 2ABCosθ

Substitute values for A, B and θ

C² = 150² + 170² - 2 * 150 * 170 * Cos 139.17

C² = 22500 + 28900 - 51000 * Cos 139.17

C² = 51400 - 51000 (−0.7567)

C² = 51400 + 38,591.7

C² = 89,991.7

Take Square Root of both sides

C = 299.9861663477167

C = 299.99 miles (Approximated)

Hence, the distance between the plane and the airport is 299.99 miles

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2+2=4

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Step-by-step explanation:

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A company studied the number of lost-time accidents occurring at its Brownsville, Texas, plant. Historical records show that 6%
Georgia [21]

Answer:

a

\% E =  0.9 \%

b

\%E_1 = 10.1 \%

Step-by-step explanation:

From the question we are told that

The probability that an employees suffered lost-time accidents last year is P(e) =  0.06

The probability that an employees suffered lost-time accident during the current year is

P(c) =  0.05

The probability that an employee will suffer lost time during the current year given that the employee suffered lost time last year is

P(c | e) =  0.15

Generally the probability that an employee will experience lost time in both year is mathematically represented as

P(c \ n \ e) =  P(e) *  P(c \ |\ e)

=> P(c \ n \ e) =  0.06*   0.15

=> P(c \ n \ e) = 0.009

Generally the percentage of employees that will experience lost time in both year is mathematically represented as

\% E =  P(e \ n \ c ) * 100

=> \% E =  0.009 * 100

=> \% E =  0.9 \%

Generally the probability that an employee will experience at least one lost time accident over the two-year period is mathematically represented as

P(e \ u \ c) =  P(e) + P(c) - P(e \ n \  c)

=> P(e \ u \ c) =  0.06 + 0.05 - 0.009

=> P(e \ u \ c) =  0.101

Generally the percentage of the employees who will suffer at least one lost-time accident over the two-year period is mathematically represented as

\%E_1 = P(e \ u \ c) *  100

=> \%E_1 = 0.101*  100

=> \%E_1 = 10.1 \%

7 0
3 years ago
a new rectangular park is planned.it will be 3/4 kilometer long and have an area of 3/8 square kilometers. how many kilometers w
kakasveta [241]

<em>The word usage in last sentence of the question is not well presented. However, I can understand that you intend to solve for the width of the park</em>

Answer:

Width = 2\ km

Step-by-step explanation:

Given

Length = \frac{3}{8}km

Area = \frac{3}{4}km^2

Required

Determine the Width

For a rectangle:

Area = Length * Width

Substitute for Area and Length

\frac{3}{4} = \frac{3}{8} * Width

Multiply both sides by \frac{8}{3}

\frac{8}{3} * \frac{3}{4} = \frac{3}{8} * \frac{8}{3}* Width

\frac{8}{3} * \frac{3}{4} =  Width

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6 0
3 years ago
3. The stem-and-leaf plot shows the cost of lamps at a department store.
77julia77 [94]

Answer:

(a) What is the median cost?
12-78

(b) Is there a mode? If so, what is it?

No there isn't

(c) What is the difference between the most expensive and least expensive lamps?

12,75-78

(d) How many lamps cost more than $20 but less than $40?

5

(e) What is the ratio of lamps that cost less than $40 to lamps that cost more than $40? Write the ratio in the simplest form.

{for less} - (12,49)   {for more} - (49,78)

Step-by-step explanation:

hope I helped if it's wrong tell me

~Ally

3 0
2 years ago
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