The area of a hall is 806 sq. ft. Its length is 5 ft greater than its width. Find the dimensions of the hall. Enter the results
1 answer:
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Using synthetic division to divide x³ + 2x² - x - 2. Since (x + 1) is the factor, we can divide by -1. See the attached file for the synthetic division. After that, we are left with x² + x - 2. This can easily be factored into (x + 2)(x - 1). The remaining factors are (x + 2) and (x - 1).
Answer: $221.76
Step-by-step explanation:
Each wall has a length of 12 and a height of 8 and there are 4 walls
(12 x 8) x 4 = 384 sq ft
multiply sq ft by cost ($0.33)
384 x 0.33 = $126.72 for the walls and door
The ceiling has a length of 12 and a width of 12
12 x 12 = 144 sq ft
multiply sq ft by cost ($0.66)
144 x 0.66 = 95.04
add the costs
126.72 + 95.04 = $221.76 total
image of drawing of room
