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7nadin3 [17]
3 years ago
9

Irene tiene una colección de 50 dvd de películas de 90 minutos de duración cada una .Si el precio de cada uno era de 11€ , ¿cuan

to cuesta la colección completa? ¿y cuantos minutos de duración tiene la colección completa?
Mathematics
1 answer:
Rainbow [258]3 years ago
3 0

To solve this problem you must apply the proccedure shown below:

1. She has a total of 50 DVDs of 90 minutes each one of them. The cost of each DVD was 11€.

2. Therefore, to calculate the total cost of the collection, you must multiply the cost of each DVD by the total number of them:

total=(11)(50)=550€

3. To calculate the total minutes of the collection, you must multiply 90 minutes by the total number of DVDs:

(90min)(50)=4500min

Therefore, the answer is: 550€ and 4500 minutes.

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Find a polynomial f(x) of degree 3 that has the following zeros.
Thepotemich [5.8K]

Answer:

f (x) = x (x + 5) (x-9)

Step-by-step explanation:

The zeros of the polynomial are all the values of x for which the function f (x) = 0

In this case we know that the zeros are:

x = 9,\  x-9 =0

x = 0

x = -5, x + 5 = 0

Now we can write the polynomial as a product of its factors

f (x) = x (x + 5) (x-9)

Note that the polynomial is of degree 3 because the greatest exponent of the variable x that results from multiplying the factors of f (x) is 3

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What are the intercepts of f(x)=(3x-4)(7x+2)
torisob [31]

Answer:

1. (-0,286; 0), (1,333; 0)

2. (0; -8)

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A stretch of highway that is 12 1/4 miles long has a speed limit signs every 7/8 of a mile. How many speed limit signs are on th
Maksim231197 [3]
Well 12 times four is 48 so you add 48 and 1 and the first fraction (12 1/4) becomes 49/4 then you multiply this by two so it becomes 98/8 now you can take 98 dived by 7 to make 14 speed limit signs on the highway
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The strength of a certain type of rubber is tested by subjecting pieces of the rubber to an abrasion test. For the rubber to be
My name is Ann [436]

Answer:

Step-by-step explanation:

Hello!

You have the hypothesis that the average weight loss for rubber after an abrasion test is less than 3.5 mg. To test this a large sample of pieces of rubber were sampled and subjected to the abrasion test.

With the given information you must test whether the researcher's hypothesis is sustained or not.

The study variable is,

X: Weight loss of rubber cured in a certain way after being subjected to the abrasion test. (mg)

There is no information about the variable distribution, but since it is said that the sample is a "large number" I'll take it as if it is bigger than 30 and apply the Central Limit Theorem to use the approximation of the sample mean to normal. This way I can use the Z-statistic for the test.

Symbolically the statistic hypothesis is:

H₀: μ ≥ 3.5

H₁: μ < 3.5

α: 0.05 (since is not listed, I'll choose one of the most common signification levels)

You have a one-tailed critical region, this means the p-value will also be one-tailed to the left of the distribution (i.e. →-∞)

The formula of the statistic is:

Z= <u> X[bar] - μ </u> ≈ N(0;1)

        δ/√n

To calculate the statistic you have to use the information given.

The sample mean X[bar]= 3.4 mg

Upper bond of 95% CI= 3.45 mg

The basic structure of a CI for the mean is

"estimator" ± "margin of error"

Upper bound is "estimator" + "margin of error"

Using the formula:

Ub= X[bar] + d ⇒ 3.45= 3.4 + d

⇒ d= 3.45 - 3.4 = 0.05

Where d is the margin of error

d= Z_{1-\alpha /2} * (δ/√n)

d= Z_{0.975} * (δ/√n)

d/Z_{0.975}= (δ/√n)

(δ/√n)= 0.05/ 1.96 = 0.0255

(δ/√n) is the denominator in the formula, corresponds to the standard deviation of the distribution.

Now you have all values and can calculate the statistic under the null hypothesis:

Z= <u> 3.4 - 3.5 </u> = -3.92

       0.0255

And the p-value:

P(Z ≤ -3.92) = 0.000044 ⇒ My Z- table goes up to P(Z ≤ -3.00) = 0.001, so using strictly the table I can say that the probability is less than 0.001.

To calculate the exact probability I've used a statistic program.

p-value < 0.001

I hope it helps!

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