How do I do the problem below -
1 answer:
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<h2>Answer with explanation:</h2>
As per given , we have
n= 1025
x=707
Critical value for 99% confidence interval :
Confidence interval :
i.e.
i.e.
i.e.
99% confidence interval for the proportion of all U.S. adults in December of 2012 who were optimistic about their finances in 2013= (0.653, 0.727)
Interpretation : We are 99% confident that the true population of all U.S. adults in December of 2012 who were optimistic about their finances in 2013 lies in interval (0.653, 0.727).