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sdas [7]
2 years ago
12

HELP EDCITE !! HELP PLEASE!!!!!!!!!!!!

Mathematics
2 answers:
Svetlanka [38]2 years ago
8 0

Answer:

easy:

6*10 / 2 = 30

6*10 would be a rectangle. a right triangle is just half the area

Degger [83]2 years ago
4 0
6*10 = 60 the area is 60
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A TRAFFIC LIGHT IS RED FOR 38 SECONDS YELLOW FOR 10 SECONDS AND GREEN FOR ONE MINUTE AND TWELVE SEONDS. IN A CONSTANTLY REPEATIN
morpeh [17]
The chance is 3/5 that the light will be green.

Added together the total seconds for the traffic light to complete the cycle is 120 (38+72 (1 min and 12 sec) +10.

And the green light proportion is: 72/120

We simplify by dividing by 12, which is a factor and we get: 6/10 that simplifies to 3/5.

Hope this helps!
7 0
3 years ago
75 points and I’ll give brainlyist and pleas show work
IRISSAK [1]

Answer:

1. y<-2   2.  x≤5   3. 0<23    4. 0 ≤ -1   5. inequality: 3 + (7x) < 24 answer: x<3

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Help me please its urgent
jek_recluse [69]
Um division divide the letters
3 0
2 years ago
Read 2 more answers
A baseball team has 4 ​pitchers, who only​ pitch, and 16 other​ players, all of whom can play any position other than pitcher. F
ivolga24 [154]

Answer:

2,075,673,600 batting orders may occur.

Step-by-step explanation:

The order of the first eight batters in the batting order is important. For example, if we exchange Jonathan Schoop with Adam Jones in the lineup, that is a different lineup. So we use the permutations formula to solve this problem.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

P_{(n,x)} = \frac{n!}{(n-x)!}

First 8 batters

8 players from a set of 16. So

P_{(16,8)} = \frac{16!}{(16 - 8)!} = 518918400

Last batter:

Any of the four pitchers.

How many different batting orders may​ occur?

4*518918400 = 2,075,673,600

2,075,673,600 batting orders may occur.

5 0
3 years ago
HELP ME PLEASEEEEEEEEEEEEEEEE
dsp73
The answer should be 18.66
7 0
2 years ago
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