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2 years ago

Solve for y:5(x + y) = 20 + 3x

2 answers:

5 0

5(x+y)= 20+ 3x
5x+5y=20+3x
5x+5y-3x=20+3x-3x
2x+5y=20
2x+5y-2x=20-2x
5y=-2x+20
5y/5=-2x/5+20/5
y=-2/5x+4

ANSWER: y=-2/5x+4

creativ13 [48]2 years ago

3 0

Answer:

???

Step-by-step explanation:

5x+5y=20+3x (distribution)

-3x -3x (alike terms)

2x+5y=20

/2x /2x

5y=20/2x

/5 /5

y=20 (idk I put it in my calculator)

if that looks nothing like the correct answer just put 0 for x and solve from there

5(0)= 0, so

5y=20 (because the three also has an x which we are putting as zero)

divide 20 by 5 and get 4

I'm really sorry if this is wrong it's been a long day

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$y = -6(x - \frac{1}{2})^2 -\frac{7}{2}$

Step-by-step explanation:

Given:

$y = -6x^2 + 3x + 2$

Required

Rewrite in vertex form

The vertex form of an equation is in form of: $y = a(x - h)^2+ k$

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Subtract 2 from both sides

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<em>Rough work</em>

The coefficient of x is $\frac{-1}{2}$

It's square is $(\frac{-1}{2})^2 = \frac{1}{4}$

Adding inside the bracket of $-6(x^2 - \frac{x}{2})$ to give: $-6(x^2 - \frac{x}{2} + \frac{1}{4})$

To balance the equation, the same expression must be added to the other side of the equation;

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The expression becomes

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$y - 2 -\frac{6}{4}= -6(x^2 - \frac{x}{2} + \frac{1}{4})$

$y - 2 -\frac{3}{2}= -6(x^2 - \frac{x}{2} + \frac{1}{4})$

Factorize the expression on the right hand side

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$y - (2 +\frac{3}{2})= -6(x - \frac{1}{2})^2$

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$y - (\frac{7}{2})= -6(x - \frac{1}{2})^2$

$y +\frac{7}{2} = -6(x - \frac{1}{2})^2$

Make y the subject of formula

$y = -6(x - \frac{1}{2})^2 -\frac{7}{2}$

<em>Solved</em>

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Solve for y:5(x + y) = 20 + 3x​

Solve for y:5(x + y) = 20 + 3x