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avanturin [10]
3 years ago
9

Solve for D Thanks!!

Mathematics
1 answer:
Verizon [17]3 years ago
5 0

Answer:

The answer is d = C/pi.

Step-by-step explanation:

To solve this equation for the variable d, we must isolate it on the right side of the equation.  It is currently being multiplied by pi, so to reverse this action, we should divide both sides of the equation by pi.

c = (pi) * d

c/pi = pi/pi * d

c/pi = d

d = c/pi

Therefore, the answer is d = C/pi.

Hope this helps!

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Please help with math and explain if u do i’ll give brainly!!
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Answer:

3/2

Step-by-step explanation:

MNOP to ABCD: The answer has to be greater than one because ABCD increases in size from MNOP.

To get the scale factor you have to compare the sides.

Line AD = 6 in.

Line MP = 4 in.

6/4 = 3/2

3 0
3 years ago
The school's basketball team lost 4 times as many games as they won. They also tied 5 fewer games than they won.
jekas [21]
Let w won games, t tied games, s lose games

s=4w

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7 0
3 years ago
Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%. Find
Papessa [141]

Answer:

1) \text{P(at least one boy and one girl)}=\frac{3}{4}

2) \text{P(at least one boy and one girl)}=\frac{3}{8}

3) \text{P(at least two girls)}=\frac{1}{2}

Step-by-step explanation:

Given : Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%.

To  Find : The probability of each event.  

1) P(at least one boy and one girl)

2) P(two boys and one girl)

3) P(at least two girls)        

Solution :

Let's represent a boy with B and a girl with G

Mr. and Mrs. Romero are expecting triplets.

The possibility of having triplet is

BBB, BBG, BGB, BGG, GBB, GBG, GGB, GGG

Total outcome = 8

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

1) P(at least one boy and one girl)

Favorable outcome =  BBG, BGB, BGG, GBB, GBG, GGB=6

\text{P(at least one boy and one girl)}=\frac{6}{8}

\text{P(at least one boy and one girl)}=\frac{3}{4}

2) P(at least one boy and one girl)

Favorable outcome =  BBG, BGB, GBB=3

\text{P(at least one boy and one girl)}=\frac{3}{8}

3) P(at least two girls)

Favorable outcome = BGG, GBG, GGB, GGG=4

\text{P(at least two girls)}=\frac{4}{8}

\text{P(at least two girls)}=\frac{1}{2}

4 0
3 years ago
Read 2 more answers
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Naddika [18.5K]

The screenshot below will give you the answer and the explanation

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Studentka2010 [4]
I hope this helps you

5 0
3 years ago
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