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Contact [7]
3 years ago
6

A rectangle has a height of 5 and a width of 4x2– 2x - 6.

Mathematics
1 answer:
joja [24]3 years ago
5 0

Answer:

area = 20x^2 - 10x - 30

Step-by-step explanation:

5(4x2 - 2x - 6)

area = 20x^2 - 10x - 30

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Determine if the equation 4x^2 - 6y^2 = 144 represents an ellipse or a hyperbola, then determine if the ellipse or hyperbola is
PilotLPTM [1.2K]
It represents a horizontal hyperbole
8 0
3 years ago
Bertha buys electricity from a company that offers a choice of two tariffs. Both have a daily charge of $0.20 regardless of how
Alenkasestr [34]

Answer: D ( 17/20)

Step-by-step explanation:

The two choices are:

The ‘standard’ tariff charges = $0.10 per unit

The ‘day/night tariff’ = $0.12 per unit for each unit consumed between 06:00 and 22:00 but only $0.05 for each unit consumed between 22:00 and 06:00

The day time is between 22:00 and 06:00

Time = 22 - 6 = 16 hours

Let assume that the charges are unit per hour.

For standard tariff = (16 × 0.10) + 0.2

Standard tariff = 1.6 + 0.2 = 1.8

For day/night = (16 × 0.12) + 0.2

= 1.92 + 0.2

= 2.12

The proportion will be

1.8/2.12 = 17/20 ( approximately)

6 0
4 years ago
Based on the graphs of f (x) and g(x), what must the domain of (f ⋅ g)(x) be?
bekas [8.4K]

Using the concept of domain, the domain of (f.g)(x) is given by:

{x ∈ ℝ | x ≠ 3}

---------------------

  • The domain of a function is given by all possible input values, that is, <u>on a graph, all values that the x-axis assumes.</u>
  • In the graph, <u>function f assumes all real values.</u>
  • Function g is not defined for x = 3, thus, it's domain is all real values except 3.
  • Thus, the multiplication, as fg(x) = f(x) \times g(x), will also not be defined at x = 3, and the domain of the multiplication is:

{x ∈ ℝ | x ≠ 3}

A similar problem is given at brainly.com/question/4175434

4 0
3 years ago
A total of 691 tickets were sold for the school play they were either adult tickets or student tickets there were fifty nine few
garri49 [273]
691 = A+ S
A=S+59
691 = S+59+S
691=2S+59
691-59 = 2S +59 -59
632 = 2S
316= S
5 0
3 years ago
Recall the scenario about Eric's weekly wages in the lesson practice section. Eric's boss have been very impressed with his work
Solnce55 [7]

Answer:  

1)\quad f(x)=\bigg\{\begin{array}{ll}12x&0\leq x

2) D: x = [0, 24]

3) R: y = [0, 384]

4) see graph

<u>Step-by-step explanation:</u>

Eric's regular wage is $12 per hour for all hours less than 9 hours.

The minimum number of hours Eric can work each day is 0.

f(x) = 12x    for   0 ≤ x < 9

Eric's overtime wage is $18 per hour for 9 hours and greater.

The maximum number of hours Eric can work each day is 24 (because there are only 24 hours in a day).

f(x) = 18(x - 8) + 12(8)

    = 18x - 144 + 96

    = 18x - 48           for 9 ≤ x ≤ 24

The daily wage where x represents the number of hours worked can be displayed in function format as follows:

f(x)=\bigg\{\begin{array}{ll}12x&0\leq x

2) Domain represents the x-values (number of hours Eric can work).

The minimum hours he can work in one day is 0 and the maximum he can work in one day is 24.

D:  0 ≤ x ≤ 24        →        D: x = [0, 24]

3) Range represents the y-values (wage Eric will earn).

Eric's wage depends on the number of hours he works. Use the Domain (given above) to find the wage.

The minimum hours he can work in one day is 0.

f(x) = 12x

f(0) = 12(0)

     =  0

The maximum hours he can work in one day is 24 <em>(although unlikely, it is theoretically possible).</em>

f(x) = 18x - 48

f(24) = 18(24) - 48

       = 432 - 48

       = 384

D:  0 ≤ y ≤ 384        →        D: x = [0, 384]

4) see graph.

Notice that there is an open dot at x = 9 for f(x) = 12x

and a closed dot at x = 9 for f(x) = 18x - 48

6 0
3 years ago
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