Answer:
The phase difference between yA and yB is
Step-by-step explanation:
Given harmonic modeled as :
yA = 8 sin(2t -
) And
yB = 8 sin(2t -
)
The function as written as :
y = a sin(ωt - Ф) where Ф is phase difference
So , phase difference between yA and yB = ( Ф_1 - Ф_2 )
Or phase difference between yA and yB = ( -
+
)
Or, phase difference between yA and yB = 
I.e phase difference between yA and yB =
Hence The phase difference between yA and yB is
Answer
Since your probably solving for W, isolate W by adding the -3n to both sides and get W=5n now use a calculator and multiply 5 and Pi. To Get 15.7.
I used N for pi since I don’t have that symbol
You need to specify what needs to be solved so I just assumed W
[/tex]

This changes to a mix fraction
3 [tex] \frac{5}{9}