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hodyreva [135]
3 years ago
7

Can anyone answer this?

Mathematics
2 answers:
Alona [7]3 years ago
8 0

Answer:

Because the triangle is isosceles, the base angles are congruent. Since the sum of angles in a triangle is 180° we can write:

24 + x + x = 180

24 + 2x = 180

2x = 156

x = 78°

BaLLatris [955]3 years ago
6 0

Answer:

\boxed{x=78}

Step-by-step explanation:

The triangle is an isosceles triangle.

The two base angles are equal.

Angles in a triangle add up to 180 degrees.

x + x + 24 = 180

Combine like terms.

2x + 24 = 180

Subtract 24 on both sides.

2x = 156

Divide both sides by 2.

x = 78

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keeping in mind that parallel lines have the same exact slope, hmmmm what's the slope of the line above anyway?

\bf 3y-x=-12\implies 3y=x-12\implies y=\cfrac{x-12}{3}\implies y = \cfrac{x}{3}-\cfrac{12}{3} \\\\\\ y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{1}{3}}x-4\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

so we're really looking for the equation of a line whose slope is 1/3 and runs through (18,2)

\bf (\stackrel{x_1}{18}~,~\stackrel{y_1}{2})~\hspace{10em} \stackrel{slope}{m}\implies \cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{\cfrac{1}{3}}(x-\stackrel{x_1}{18}) \\\\\\ y-2=\cfrac{1}{3}x-6\implies y=\cfrac{1}{3}x-4

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In the data set below, what is the range? 9, 4, 9, 2, 8, 2, 1
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Which graph represents the line y=−3x+4?
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Step-by-step explanation:

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3 years ago
Read 2 more answers
Do i solve this?? need help???
Arlecino [84]
A =
5 and -5
-1 and 3

¹/₃B =

-6 and 12
-7 and 7

¹/₃B + A =

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3 years ago
In the right triangle ABC shown, c=17ft and angle A=30 degrees Determine side a
jekas [21]

Using relations in a right triangle, considering c as the hypotenuse, we have that the length of side A is: a = 8.5\sqrt{3}

<h3>What are the relations in a right triangle?</h3>

The relations in a right triangle are given as follows:

  • The sine of an angle is given by the length of the opposite side to the angle divided by the length of the hypotenuse.
  • The cosine of an angle is given by the length of the adjacent side to the angle divided by the length of the hypotenuse.
  • The tangent of an angle is given by the length of the opposite side to the angle divided by the length of the adjacent side to the angle.

From the information given, we can build the following relation:

cos(A) = a/c.

\frac{\sqrt{3}}{2} = \frac{a}{17}

a = \frac{17\sqrt{3}}{2}

a = 8.5\sqrt{3}

More can be learned about relations in a right triangle at brainly.com/question/26396675

#SPJ1

6 0
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