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Lera25 [3.4K]
3 years ago
7

If L, M and N are midpoints of the sides of PQR, PR = 46, PQ = 40, and LN=17, find each measure

Mathematics
1 answer:
Serga [27]3 years ago
5 0

Check the picture below.

let's recall that the midsegment of a triangle is the segment that's half-way to both endsides and is at the same time parallel to the 3rd side, is also half the length of the parallel side, so-called the base.

so, for example, we know L, M and N are midpoints to each segment, that means that LM is a midsegment and parallel to PR and also half the length of PR, same is true for LN and MN.

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- What is the area of the figure below? Use 3.14<br> for T.<br> 7 cm<br> 22 cm<br> 18 cm
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Answer: \Large\boxed{Total~area=586.17~cm^2}

Step-by-step explanation:

<h2>PART I: Find the area of the triangle</h2>

<u>Given information</u>

Height=7~cm

Base=18~cm

<u>Given formula</u>

A=b\times h\times\dfrac{1}{2}

A=Area\\b=base\\h=height\\

<u />

<u>Substitute values into the formula</u>

A=(7)\times (18)\times\dfrac{1}{2}

<u>Simplify by multiplication</u>

A=(7)\times 9

A=63~cm^2

<h2>PART II: Find the area of the rectangle</h2>

<u>Given information</u>

Height = 18~cm

Base=22~cm

<u>Given formula</u>

A=b\times h

A=Area\\b=base\\h=height\\

<u />

<u>Substitute values into the formula</u>

A=(22)\times (18)

<u>Simplify by multiplication</u>

A=396~cm^2

<h2>PART III: Find the area of the half-circle</h2>

<u>Given information</u>

Diameter = 18 cm

<u>Given formula</u>

A=(\dfrac{d}{2} )^2\times \pi \div2

A=Area\\d=diameter

<u>Substitute values into the formula</u>

A=(\dfrac{18}{2} )^2\times (3.14) \div2

<u>Simplify the fraction</u>

A=(9 )^2\times (3.14) \div2

<u>Simplify the exponents</u>

A=81\times (3.14) \div2

<u>Simplify by multiplication</u>

A=254.34\div2

<u>Simplify by division</u>

A=127.17~cm^2

<h2>PART IV: Find the total area</h2>

<u>Given formula</u>

Total~area=Triangle+Rectangle+circle~(half)

<u>Substitute values into the formula</u>

Total~area=(63)+(396)+(127.17)

<u>Simplify by addition</u>

Total~area=459+(127.17)

\Large\boxed{Total~area=586.17~cm^2}

Hope this helps!! :)

Please let me know if you have any questions

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