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Lera25 [3.4K]
3 years ago
7

If L, M and N are midpoints of the sides of PQR, PR = 46, PQ = 40, and LN=17, find each measure

Mathematics
1 answer:
Serga [27]3 years ago
5 0

Check the picture below.

let's recall that the midsegment of a triangle is the segment that's half-way to both endsides and is at the same time parallel to the 3rd side, is also half the length of the parallel side, so-called the base.

so, for example, we know L, M and N are midpoints to each segment, that means that LM is a midsegment and parallel to PR and also half the length of PR, same is true for LN and MN.

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Help with these please.
zepelin [54]
For numbers 15-17, we need to remember that two of a triangle's angles are always acute and the third angle will allow us to classify the triangle based on its angles. now that we know this, let's look at #15. the first two angles listed are acute, and the third is an obtuse angle, therefore it is an obtuse triangle. on #16 we have three acute angles, so it is an acute triangle. #17 has two acute angles and a right angle so it is a right triangle.
on numbers 21-23, we need to know that a triangle with all congruent sides is called equilateral, a triangle with two equal sides is isosceles, and a triangle with no equal sides is called scalene. #21 shows two equal sides so it is an isosceles triangle. #22 has three equal sides so it is an equilateral triangle. #23 has no equal sides so it is scalene. hope this helped! :)
7 0
3 years ago
Given the polynomial function below, find F(-1).
mrs_skeptik [129]

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f(x) =  -  {x}^{3}  -  {x}^{2}  + 1

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f( - 1) =  -  ({ - 1})^{3} -  ({ - 1})^{2} + 1 \\

f( - 1) =  - ( - 1) - (1) + 1

f( - 1) = 1  - 1 + 1

f( - 1) = 2 - 1

f( - 1) = 1

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

The correct answer is (( D )) .

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3 0
3 years ago
What is the perimeter of the triangle shown on the coordinate plane, to the nearest tenth of a unit?
Akimi4 [234]

Answer:

25.6 units

Step-by-step explanation: From the figure we can infer that our triangle has vertices A = (-5, 4), B = (1, 4), and C = (3, -4).

First thing we are doing is find the lengths of AB, BC, and AC using the distance formula:

d=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}

where

(x_1,y_1) are the coordinates of the first point

(x_2,y_2) are the coordinates of the second point

- For AB:

d=\sqrt{[1-(-5)]^{2}+(4-4)^2}

d=\sqrt{(1+5)^{2}+(0)^2}

d=\sqrt{(6)^{2}}

d=6

- For BC:

d=\sqrt{(3-1)^{2} +(-4-4)^{2}}

d=\sqrt{(2)^{2} +(-8)^{2}}

d=\sqrt{4+64}

d=\sqrt{68}

d=8.24

- For AC:

d=\sqrt{[3-(-5)]^{2} +(-4-4)^{2}}

d=\sqrt{(3+5)^{2} +(-8)^{2}}

d=\sqrt{(8)^{2} +64}

d=\sqrt{64+64}

d=\sqrt{128}

d=11.31

Next, now that we have our lengths, we can add them to find the perimeter of our triangle:

p=AB+BC+AC

p=6+8.24+11.31

p=25.55

p=25.6

We can conclude that the perimeter of the triangle shown in the figure is 25.6 units.

Read more on Brainly.com - brainly.com/question/12560433#readmore

8 0
3 years ago
Hey guys please help with both
podryga [215]
1/2 *(a+b)-(a-b)²
a=18, b=14
1/2 *(18+14)-(18-14)²=1/2 *(18+14)-(18-14)²= 1/2*32-4²=16-16=0
answer D

answer B 
2 factors have 2 terms: (x+4) and (y+4)

5 0
3 years ago
Center (0,0); r= square root of 12
Vitek1552 [10]
<span>(4,5); r= square root of 12</span>
5 0
3 years ago
Read 2 more answers
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