Answer:
a) ![\frac{dA}{dt} = \pi 2r \frac{dr}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7BdA%7D%7Bdt%7D%20%3D%20%5Cpi%202r%20%5Cfrac%7Bdr%7D%7Bdt%7D)
b) area of the spill increasing when the radius is 23 m
![\frac{dA}{dt} = 46\pi m/s](https://tex.z-dn.net/?f=%5Cfrac%7BdA%7D%7Bdt%7D%20%3D%2046%5Cpi%20m%2Fs)
Step-by-step explanation:
<u>Explanation:</u>-
a)
Given 'A' is the area of a circle with radius 'r'
The area of the circle
..(I)
Differentiating equation (I) with respective to 't'
![\frac{dA}{dt} = \pi 2r \frac{dr}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7BdA%7D%7Bdt%7D%20%3D%20%5Cpi%202r%20%5Cfrac%7Bdr%7D%7Bdt%7D)
b)
If the radius of the oil spill increases at a constant rate of 1 m/s
Given the radius r= 23m
Area of the spill increasing when the radius is 23 m
![\frac{dA}{dt} = \pi (2)(23) (1) =46\pi m/s](https://tex.z-dn.net/?f=%5Cfrac%7BdA%7D%7Bdt%7D%20%3D%20%5Cpi%20%282%29%2823%29%20%281%29%20%3D46%5Cpi%20m%2Fs)
The formula to solve a cylinder is V=πr²h
So, round pi to 3.14
We must plug in for the radius (r) in this equation. To do this, we must half up the diameter, 5. 5/2 = 2.5
6 is height
V=3.14 * 2.5² * 6
V=117.81 we must round though to tenth, and that would be:
Answer V=117.8m³
Answer:
cant see
Step-by-step explanation:
IDK
Answer:
A
Step-by-step explanation:
the point is at positive 8 and none of the other answers have positive 8
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