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2 years ago

Solve for x parallel

Mathematics

1 answer:

umka2103 [35]2 years ago

8 0

Answer:

x=5

Step-by-step explanation:

Hi there! So when it comes to these two angles, you have to set them equal to each other. From there, you have to isolate the x values, so I subtracted x from the 3x and added 15 to the -5. If you plug in the 5 for the x values, both give the value of 0, so it all checks out. I hope this helped! Please mark this as brainliest if I managed to get this correct. <3

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Well i would do this 32*3=96 but not sure.

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3 years ago

you currently have 24 credit hours and a 2.8 gpa you need a 3.0 gpa to get into the college. if you are taking a 16 credit hours

Juliette [100K]

Answer:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Step-by-step explanation:

For this case we know that the currently mean is 2.8 and is given by:

$\bar X = \frac{\sum_{i=1}^n w_i *X_i }{24} = 2.8$

Where $w_i$ represent the number of credits and $X_i$ the grade for each subject. From this case we can find the following sum:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

6 0

3 years ago

The bedroom and office in the diagrams below are similar rectangles. The walls on the left sides in the diagram are proportional

kari74 [83]

Answer:

D. 16.8

Step-by-step explanation:

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3 years ago

A car moving at a constant speed passed a timing device at t=0. After 9 seconds, the car has traveled 837 ft. Write a linear fu

diamong [38]

Answer:

at t=0 the car has moved 0 feet, also you know it has a constant speed so you get the points:

P1:(0,0) therefore you know b, the y-intercept=0

P2:(8,840)

insert P2 into y=mx+b

840=8m+0

840/8=m

105=m

so the result is:

y=105x=105t=f(t)=d

Step-by-step explanation:

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3 years ago

Which is the focus of a parabola with equation y2 = 4x?

statuscvo [17]

Answer:

(1, 0)

Step-by-step explanation:

Please write this as y^2 = 4x; the " ^ " indicates exponentiation.

The appropriate equation for a horizontal parabola that opens to the right is

y^2 = 4px

Here, we are told that y^2 = 4x; this tells us that 4p = 4, and so p = 1.

Again, this parabola is a horizontal one and it opens to the right. p = 1 is the distance of the focus from the vertex, and in this case p = 1. Thus, the focus is at (1, 0) (situated on the x-axis).

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3 years ago

Solve for x parallel ​

Solve for x parallel