6.6× 101/03 ×107 can sum one plz help me with this question

Mathematics

2 answers:

Marianna [84]3 years ago

8 0

Answer:

The answer would be 23,775.4

Step-by-step explanation:

Vladimir [108]3 years ago

6 0

If how u set the question up as in (101 is divided by 03?) then the answer would be 23775.4

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Anyone know the answer??

Serggg [28]

Answer:

the second option

Step-by-step explanation:

in ax²+bx+c = 0:

$x = \frac{-b+-\sqrt{b^2-4ac} }{2a}$

subtract both sides by 6 to get to this form, as the right side will be left with 0

6x² + 8x - 6 = 0

here, the coefficient for x² (a) is 6, the coefficient for x (b) is 8, and the remaining number added on (c) is -6

plugging our numbers into the formula, we get

$x = \frac{-8+-\sqrt{(-8)^2-4(6)(-6)} }{2(6)}\\= \frac{-8+-\sqrt{64-(-144)} }{12} \\= \frac{-8+-\sqrt{208} }{12} \\ = \frac{-8+\sqrt{208} }{12} or \frac{-8-\sqrt{208} }{12}\\= 0.53518375848 or -1.86851709182\\= approximately -1.87, 0.54$

8 0

2 years ago

Determine the greatest common divisor of the elements of the set \[ s = \{ n^{13} - n \mid n \in \mathbb{z} \}. \]

Kay [80]

Answer:

2730

Step-by-step explanation:

We want to determine the greatest common divisor of the elements of the set $S = \{ n^{13} - n \mid n \in \mathbb{Z} \}.$

We apply the Fermat's little theorem which states that if p is a prime number, then for any integer a, the number aᵖ − a is an integer multiple of p.

Now, $n^{13} \equiv n \mod p$ if p-1 divides 12.