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Alexeev081 [22]
3 years ago
7

Nevaeh has $0.80 worth of nickels and dimes. She has a total of 11 nickels and dimes altogether. Graphically solve a system of e

quations in order to determine the number of nickels, x, and the number of dimes, y, that Nevaeh has.
Mathematics
1 answer:
Tanya [424]3 years ago
8 0

Answer:

18

Step-by-step explanation:

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Darcy house is 6 times as far from school as her friends house. if her friends house is 3/4 mile from school how many miles from
laiz [17]
3.75 miles because 3/4 is .75 in money and the 3 is howm many miles

6 0
3 years ago
Find the point where the line crosses the x-axis. y = –5x + 5
Ronch [10]
Every point on the x-axis has y-coordinate 0.
Let y = 0, and solve for x.

y = -5x + 5

0 = -5x + 5

5x = 5

x = 1

The line crosses the x-axis at x = 1.
8 0
3 years ago
What is the radical form of the expression (2x^4y^5)^3/8
s344n2d4d5 [400]

We are given expression: (2x^4y^5)^{3/8}

Let us distribute 3/8 over exponents in parenthesis, we get

(2^{3/8}x^{4\times 3/8}y^{5\times 3/8}) = (2^{3/8}x^{12/8}y^{15/8})

= (2^{3/8}x^{1\frac{4}{8}} y^{1\frac{7}{8}} )

We can get x and y out of the radical because, we get whlole number 1 for x and y exponents for the mixed fractions.

So, we could write it as.

(2^{3/8}x^{1\frac{4}{8}} y^{1\frac{7}{8}} ) = xy(2^{\frac{3}{8} }x^{\frac{4}{8}} y^{\frac{7}{8}} )

Now, we could write inside expression of parenthesis in radical form.

xy\sqrt[8]{2x^{3}x^4y^7}

8 0
3 years ago
The sum of 2 numbers (x and y) is 20, and their product is 51. What are the values of x and y
Murljashka [212]

Answer: 13&7

Step-by-step explanation:

The sum of two numbers x&y is 20

Product of the 2numbers xy is 51

X+y=20......equation 1

XY=51.........equation 2

X=20-y.......equation 3

Substitute for x inequation 3 into equation 2

So we have;

(20-y)y=51

Open the bracket

20y-y^2=51

Collect like terms,so we have

Y2-20y+51=0

Factorise

Factors of 51 is 13&7

So -13-7=-20 &-13×-7=51

Substitute

Y2-13y-7y+51=0

Y(y-13)-7(y-13)=0

(Y-7)(y-13)=0

Y-7=0

Y=7 or

Y-13=0

Y=13

Y=13 or 7

Substitute for y in equation 1

X+y=20

X+7=20

X=20-7

X=13 or

X+13=20

X=20-13

X=7

Therefore, X &Y = 13 &7

4 0
2 years ago
Tn = -2n + 3, find t4
yanalaym [24]

Substitute n = 4

t(4)=-2(4)+3

-8+3= -5

therefore t(4) = -5

4 0
3 years ago
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