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Mamont248 [21]
3 years ago
6

A function test() that would take three integervalues x, y and z (as

Computers and Technology
1 answer:
marta [7]3 years ago
4 0

Answer: The c++ program to implement test() method is given below.

#include <iostream>

using namespace std;

int test(int a, int b, int c);

int main() {

   int x, y, z;

   cout<<"This program displays the largest number."<<endl;

       cout<<"Enter first number"<<endl;

       cin>>x;

       cout<<"Enter second number"<<endl;

       cin>>y;

       cout<<"Enter third number"<<endl;

       cin>>z;

   int max = test(x, y, z);

   cout<<"The largest number is "<<max<<endl;

   return 0;

}

int test(int a, int b, int c)

{

   if((a>b)&&(a>c))

       return a;

 

   else if((b>a)&&(b>c))

           return b;

           

   else if((c>b)&&(c>a))

           return c;

     

}

OUTPUT

This program displays the largest number.

Enter first number

12

Enter second number

0

Enter third number

-87

The largest number is 12

Explanation:

The method test() is declared as follows.

<em>int test(int a, int b, int c);</em>

The method is declared with return type int since it returns an integer, i.e., the largest of the three parameters.

This program is designed to accept 0 and all values of integers. Hence, input is not tested for validity. It is assumed that the user enters only numerical values.

The program declares and uses three integer variables to store the user input.

<em>int x, y, z;</em>

The method test() is designed to accept three integer parameters. This method is called once the user enters three numbers for comparison.

<em>int test(x, y, z);</em>

These numbers are compared in order to return the largest number.

No variable is used for comparison. The method simply compares the numbers using multiple if-else statements.

<em>if((a>b)&&(a>c))</em>

<em>        return a;</em>

The same comparison logic is applied for other two input values.

The largest number is returned to the calling function which is main() in this program. This value is stored in the integer variable, max, declared in the main() method. The variable max is declared and initialized simultaneously.

<em>int max = test(x, y, z);</em>

This value is then displayed on the screen.

<em>cout<<"The largest number is "<<max<<endl;</em>

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Write a static method that implements a recursive formula for factorials. Place this method in a test program that allows the us
matrenka [14]

Answer:

Written in Java

import java.util.*;

public class Main {

  public static int fact(int n) {

     if (n == 1)

        return n;

     else

        return n * fact(n - 1);

  }

  public static void main(String[] args) {

     int num;

     Scanner input = new Scanner(System.in);

     char tryagain = 'y';

     while(tryagain == 'y'){

     System.out.print("Number: ");

     num = input.nextInt();

     System.out.println(num+"! = "+ fact(num));

     System.out.print("Try another input? y/n : ");

     tryagain = input.next().charAt(0);

}        

  }

}

Explanation:

The static method is defines here

  public static int fact(int n) {

This checks if n is 1. If yes, it returns 1

     if (n == 1)

        return n;

If otherwise, it returns the factorial of n, recursively

     else

        return n * fact(n - 1);

  }

The main method starts here. Where the user can continue executing different values of n. The program keep prompting user to try again for another number until user signals for stoppage

  public static void main(String[] args) {

This declares num as integer

     int num;

     Scanner input = new Scanner(System.in);

This initializes tryagain as y

     char tryagain = 'y';

This checks if user wants to check the factorial of a number

     while(tryagain == 'y'){

This prompts user for input

     System.out.print("Number: ");

This gets user input

     num = input.nextInt();

This passes user input to the function and also prints the result

     System.out.println(num+"! = "+ fact(num));

This prompts user to try again for another value

     System.out.print("Try another input? y/n : ");

This gets user response

     tryagain = input.next().charAt(0);

}        

Download txt
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2 years ago
If you weigh 100 pounds, and your 150 pound big sister is sitting 15 feet from the fulcrum of a seesaw, how far from the fulcrum
Dahasolnce [82]

Answer:

22.5

Explanation:

My weight = 100 pounds

Sister's weight = 150

Distance from fulcrum = 15 ft

Distance has an inverse proportion with weight

Distance = k/w

Where k is a constant

K = distance x weight

K = 100 x distance

150 x 15 = 100 distance

2250 = 100 distance

Divide through by 100 to get distance

2250/100 = distance

Distance = 22.5

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3 years ago
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