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3 years ago

How to do part iii please

Mathematics

1 answer:

Vsevolod [243]3 years ago

5 0

Answer:

-In mathematics, the argument is a multi-valued function operating on the nonzero complex numbers. With complex number z visualized as a point in the complex plane, the argument of z is the angle between the positive real axis and the line joining the point to the origin, shown as φ in figure 1 and denoted arg z. To define a single-valued function, the principal value of the argument (sometimes denoted Arg z) is used. It is chosen to be the unique value of the argument that lies within the interval (–π, π].

Step-by-step explanation:

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Consider the linear function that is represented by the equation y = negative 10 x + 6 and the linear function that is represent

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3 years ago

Read 2 more answers

The ratio of the number of dogs the number of cats is 4:5. There are 270 animals on the rescue Farm. The number of dogs is 4/5.

mafiozo [28]

Answer:

Here is the complete question:

The ratio of the number of dogs to the number of cats is 4:5. There are 270 animals on the rescue farm. for each of the following statements, explain whether statements is true or false and why:

a. The number of dogs is 4/5 the number of cats.

b. 4/5 of the pets at the farm are dogs.

c. There are exactly 30 more cats than dogs.

d. There are exactly 30 dogs at the farm.

e. 5/9 of the pets at the farm are cats.

a,c and e are true statements.

Step-by-step explanation:

Let the number of dogs be "d' and number of cats be "c".

According to the question:

⇒ $c+d=270$ ...equation (i)

Arranging the ratio:

⇒ $\frac{4}{5} = \frac{d}{c}$

⇒ $4c=5d$

⇒ $c=(\frac{5}{4})d$ ...equation (ii)

Plugging (ii) in equation (i).

⇒ $c+d=270$

⇒ $\frac{5}{4} d+d=270$

⇒ $\frac{5d+4d}{4} =270$

⇒ $9d=270\times 4$

⇒ $d=\frac{270\times 4}{9}$

⇒ $d=120$

Number of dogs "d" = 120

Number of cats "c" = (270-120) = 150

Lets check each statement:

The number of dogs is 4/5 the number of cats.

⇒ $\frac{4}{5} \times 150$

⇒ $\frac{4\times 150}{5}$

⇒ $120$

Statement is true.

4/5 of the pets at the farm are dogs.

⇒ $\frac{4}{5} \times 270$

⇒ $216$

Number of dogs = 120

So the above statement is false.

There are exactly 30 more cats than dogs.

⇒ $c-d =30$

⇒ $150-120=30$

Statement is true.

There are exactly 30 dogs at the farm.

False, as there are 120 dogs

5/9 of the pets at the farm are cats.

⇒ $\frac{5}{9} \times 270$

⇒ $150$

Statement is true.

So,

Statement a,c and e are true as we could observe in the explanation.

8 0

3 years ago

F(x)=7x+9 find f(6c-4) a.35c+9 b.42c+9 c.42c-19 d.42c-19

Lapatulllka [165]

C & D Answer Choices Are The Same, Your Answer Is 42c-19

$f(x) = \: all \: x \: in \: (7x + 9)$
$f(x) = 7x + 9$
$f(6c - 4) = 7x + 9$
*Distributive Property
$f(6c - 4) = 7(6c - 4) + 9$
$f(6c - 4) = 42c - 28 + 9$
$f(6c - 4) = 42c - 19$

4 0

3 years ago