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3 years ago

14

Elena has 20 apples and 35 crackers for making snack bags. She wants to make as many snack bags as possible and wants each bag t

o have the same combination of apples and crackers. What is the largest number of snack bags she could make?

2 answers:

sattari [20]3 years ago

6 0

Answer: 5 because it is the greatest common factor

Yuliya22 [10]3 years ago

6 0

I think the answer is 5 because 5 is the greatest common factor.

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The price of a gallon of milk increased from $5.50 to $7.50. Describe the price increase as a percent.

sweet [91]

Step-by-step explanation:

7.50= (1 + x/100 ) × 5.50

7.50/ 5.50 = 1+x/100

x/100 = 0.36

x= 36.36%

6 0

3 years ago

Triangle PQR is transformed to triangle P'Q'R'. Triangle PQR has vertices P(4, 0), Q(0, −4), and R(−8, −4). Triangle P'Q'R' has

Whitepunk [10]

Answer:

Please find attached the required plot accomplished with an online tool

Part A:

1/4

Part B:

P''(-1, 0), Q''(0, -1), and R''(2, -1)

Part C:

Triangle PQR is similar to triangle P''Q''R'' but they are not congruent

Step-by-step explanation:

Part A:

Triangle ΔPQR has vertices P(4, 0), Q(0, -4), R(-8, -4)

Triangle ΔP'Q'R' has vertices P'(1, 0), Q'(0, -1), R'(-2, -1)

The dimensions of the sides of the triangle are given by the relation;

$l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

Where;

(x₁, y₁) and (x₂, y₂) are the coordinates on the ends of the segment

For segment PQ, we place (x₁, y₁) = (4, 0) and (x₂, y₂) = (0, -4);

By substitution into the length equation, we get;

The length of segment PQ = 4·√2

The length of segment PR = 4·√10

The length of segment RQ = 8

The length of segment P'Q' = √2

The length of segment P'R' = √10

The length of segment R'Q' = 2

Therefore, the scale factor of the dilation of ΔPQR to ΔP'Q'R' is 1/4

Part B:

Reflection of (x, y) across the y-axis gives;

(x, y) image after reflection across the y-axis = (-x, y)

The coordinates after reflection of P'(1, 0), Q'(0, -1), R'(-2, -1) across the y-axis is given as follows;

P'(1, 0) image after reflection across the y-axis = P''(-1, 0)

Q'(0, -1) image after reflection across the y-axis = Q''(0, -1)

R'(-2, -1) image after reflection across the y-axis = R''(2, -1)

Part C:

Triangle PQR is similar to triangle P''Q''R'' but they are not congruent as the dimensions of the sides of triangle PQR and P''Q''R'' are not the same.

6 0

3 years ago

Karen purchased a DVD player on sale. The original selling price was $171.50. The sale price was $145.22. What is the first st

Kaylis [27]

Answer:

15% off

Step-by-step explanation:

5 0

3 years ago

In the diagram, polygon ABCD is flipped over a line of reflection to form a polygon with its vertices at A, B, and D are shown,

Arada [10]

The answer is point C' is (6,2).

8 0

3 years ago

Read 2 more answers

Please help! thanks so much

Stels [109]

Answer:

See below.

Step-by-step explanation:

First, we can see that $\lim_{x \to 2} (f(x))= -1$ .

Thus, for the question, we can just plug -1 in:

$\lim_{x \to 2} (\frac{x}{f(x)+1})=\frac{(2)}{-1+1} =und.$

Saying undefined (or unbounded) will be correct.

However, note that as x approaches 2, the values of y decrease in order to get to -1. In other words, $f(x)$ will always be greater or equal to -1 (you can also see this from the graph). This means that as x approaches 2, f(x) will approach -.99 then -.999 then -.9999 until it reaches -1 and then go back up. What is important is that because of this, we can determine that:

$\lim_{x \to 2} (\frac{x}{f(x)+1})=\frac{(2)}{-1+1} = +\infty$

This is because for the denominator, the +1 will always be greater than the f(x). This makes this increase towards positive infinity. Note that limits want the values of the function as it approaches it, not at it.

4 0

3 years ago