Answer:
The value of the standard error for the point estimate is of 0.0392.
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean 
and standard deviation 
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation 
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean 
and standard deviation 
In a randomly selected sample of 100 students at a University, 81 of them had access to a computer at home.
This means that 
Give the value of the standard error for the point estimate.
This is s. So
The value of the standard error for the point estimate is of 0.0392.
Answer:
RQ = 18
Step-by-step explanation:
KR is an angle bisector and divides the opposite side into segments that are proportional to the other two sides, that is
= 
, substitute values
= 
( cross- multiply )
45(38 - x) = 50x ← distribute left side
1710 - 45x = 50x ( add 45x to both sides )
1710 = 95x ( divide both sides by 95 )
18 = x
That is RQ = 18
The equation is 49 times .15 which equals 7.35 then you add that to 49 which equals 56.35. Hope that helps and sorry if its wrong
Answer:
J=-50
Step-by-step explanation:
Pupils that chose Band: 60%
Pupils that chose Chorus: 40%
Boys in band: 70%
Boys in chorus: 30%
Probability of choosing boy = Probability of boy in band + Probability of boy in chorus
P = 0.6 x 0.7 + 0.4 x 0.3
P = 0.54
The answer is D.
