Given:
Total number of students = 27
Students who play basketball = 7
Student who play baseball = 18
Students who play neither sports = 7
To find:
The probability the student chosen at randomly from the class plays both basketball and base ball.
Solution:
Let the following events,
A : Student plays basketball
B : Student plays baseball
U : Union set or all students.
Then according to given information,
We know that,
Now,
It means, the number of students who play both sports is 5.
The probability the student chosen at randomly from the class plays both basketball and base ball is
Therefore, the required probability is 
.
The Correct answer is C. -14 + (-10) = -24 and 2 + (-28) = -26. When negative numbers are in play, the lower negative number is higher in value. So when solved -24 > -26
Answer:
Step-by-step explanation:
Try and become familiar with a program like Desmos. It will do wonderful things for you.
I have graphed
Red: y = -2x + 5 (The 5 is the y intercept. For this question it could be anything.
Blue: y = - 4x + 5 Same note as above.
For question one:
First class goes from 8:00 to 9:00 second class starts 10 mins later at 9:10 and goes to 10:10. Ten minute break again 3rd class starts at 10:20, goes to 11:20. 10 min break again, fourth class starts 10 mins later at 11:30 and goes to 12:30. The answer for 1 is 12:30
a+b=350 => a=350 - b
3a + 5b = 1450
3(350-b)+b=1450
1050-3b+5b=1450
2b=400
b=200
a=150
