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3 years ago

PLEASE HELP ME! I know how to do slope. I just don't understand what they want me to do.

Mathematics

1 answer:

RideAnS [48]3 years ago

8 0

Answer: they want you to find out which coordinates makes the equation true or matches the equation (btw is the last one on the chart).

Step-by-step explanation:

Substitute a and b with the numbers on the chart to see which coordinates make the equation true. The answer is (2,0).

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2x^2y^3z^2 · 4xy^4x^2<br><br> Multiply and simplify

Advocard [28]

Take out the constants

(2 × 4)x^2xx^2y^3y^4z^2

Simplify 2 × 4 to 8

8x^2xx^2y^3y^4z^2

Use the Product Rule: x^ax^b = x^a + b

8x^2 + 1 + 2y^3 + 4z^2

Simplify 2 + 1 + 2 to 5

8x^5y^3 + 4z^2

Simplify 3 + 4 to 7

6 0

3 years ago

Two cyclists leave towns 253 kilometers apart at the same time and travel towards each other. One cyclist travels 5km/h faster t

Sladkaya [172]

Answer:

The rate of the slower cyclist is

$22\frac{4}{5}km/h$

and that of the faster cyclist is

$27 \frac{4}{5}km/h$

Step-by-step explanation:

We let x be the rate of the slower cyclist

$rate \times time = distance$

From the question, the distance between the two towns is 253 and the time taken for the two cyclist to meet is 5 hours

so we can write the equation

$5x + 5(x + 5) = 253$

We simplify to get the value for x

$\implies5x + 5x + 25 = 253$

$\implies10x = 253 - 25$

$\implies10x = 228$

$\implies x =22 \frac{4}{5}$

Hence the rate of the slower cyclist is

$22 \frac{4}{5} km/h$

and that of the rate faster cyclist is

$27 \frac{4}{5}km/h$

5 0

3 years ago

Scale drawing of the gym.

Law Incorporation [45]

Answer: The width of the new gym is 40 meters,

the length and width of the new gym are

✔ 2

times the length and width of the old gym.

Step-by-step explanation:

Pls give brainliest!! Have a nice day!!

8 0

3 years ago

Read 2 more answers

How do you convert 4 over 16 to a decimal

Elina [12.6K]

4.16 because that is what I got in the answer

8 0

3 years ago

Read 2 more answers

Your friend, Isabel, has a credit card with an APR of 19.9%! How many dollars would she pay as a finance charge for just 1 month

Mazyrski [523]

Answer:

$16.583

Step-by-step explanation:

Given :Your friend, Isabel, has a credit card with an APR of 19.9%!

To Find : How many dollars would she pay as a finance charge for just 1 month on a $1000 charge?

Solution:

We are given that finance charge for just 1 month on a $1000 charge.

So, Finance charge = $\frac{19.9\% \times 1000}{12}$

Finance charge = $\frac{\frac{199}{1000}\times 1000}{12}$

Finance charge = $\frac{199\times 1000}{12}$

Finance charge = $16.583$

Hence she pay $16.583 as a finance charge for just 1 month on a $1000 charge.

6 0

4 years ago