Answer:
n = ±6 .
Step-by-step explanation:
A quadratic equation is given to us and we need to find out the solution of the given equation . The given equation is ,
Subtracting 18 both sides ,
Multiplying both sides by -2 ,
On simplyfing , we get ,
Putting squareroot both sides ,
This equals to ,
<u>Hence</u><u> the</u><u> </u><u>value</u><u> of</u><u> </u><u>n </u><u>is </u><u>±</u><u>6</u><u> </u><u>.</u>
Answer:
9 correct
Step-by-step explanation: 60% of 15 = 9
-√5/2+√5+1
-√5/2+2√5/2+1
√5/2+1
(√5+2)/2
So basically the ladder is creating a right triangle with the ground and the wall. Ladder is the hypotenuse (h), building = b, ground = g
b = h - 22 ft
g = 1010 ft
use Pythagorean Theorem to determine the length of h:

The h^2 terms cancel out to = 0
Answer:
<em>The voltage at the middle source is</em> 
Step-by-step explanation:
<u>Voltage Sources in Series</u>
When two or more voltage sources are connected in series, the total voltage is the sum of the individual voltages of each source.
The figure shown has three voltage sources of values:



The sum of these voltages is:

Operating:

We know the total voltage is
, thus:

Equating the real parts and the imaginary parts independently:
4+a=6
1+b=-3
Solving each equation:
a = 2
b = -4
The voltage at the middle source is 