![2\sqrt5+3\sqrt5-\sqrt5=(2+3-1)\sqrt5=4\sqrt5\\\\\text{Answer:}\ 4\sqrt5](https://tex.z-dn.net/?f=2%5Csqrt5%2B3%5Csqrt5-%5Csqrt5%3D%282%2B3-1%29%5Csqrt5%3D4%5Csqrt5%5C%5C%5C%5C%5Ctext%7BAnswer%3A%7D%5C%204%5Csqrt5)
Look at the square root like "x", then
Using it's concept, it is found that the odds that the winner shops in the store 4 or more times a week are given by: 9:41.
<h3>What is the odd of an event?</h3>
It is given by the <u>number of desired outcomes divided by the number of non-desired outcomes</u>.
Researching the problem on the internet, it is found that 18% of the winners shop in the store 4 or more times a week, while 82% do not, hence:
18:82 = 9:41
The odds that the winner shops in the store 4 or more times a week are given by: 9:41.
More can be learned about odds at brainly.com/question/25683609
The first thing we have to do is to calculate the
midpoint of the min and max speeds. We are given that the min and max is 74 and
95 respectively. The midpoint is then calculated as (max+min) / 2. Therefore:
midpoint = (74 + 95) / 2 = 84.5
Next, we calculate the distance from the midpoint to the
endpoint by doing subtraction. Therefore:
min endpoint: 84.5 – 74 = 10.5
max endpoint: 95 – 84.5 = 10.5
Now we know that v minus the midpoint will equal the
distance such that:
| v - midpoint | = distance.
To our problem,
| v – 84.5 | = 10.5
The answer is D because the first number doesn’t reapeat