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Ira Lisetskai [31]
3 years ago
13

(x-8)(x-k) = x^2 - 5kx +m. In the equation above, k and m are constants. If the equation is true for all values of x, what is th

e value of m?
Mathematics
1 answer:
suter [353]3 years ago
6 0
(x-8)(x-k) = x^2 - 5kx +m\\
x^2-kx-8x+8k=x^2 - 5kx +m\\
x^2-(k+8)x+8k=x^2 - 5kx +m\\\\
-(k+8)=-5k\\8k=m\\\\
-(k+8)=-5k\\
-k-8=-5k\\
4k=8\\
k=2\\\\
m=8\cdot2\\
\boxed{m=16}

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