How can you solve the equation 8x = 2x + 2 graphically?

Mathematics

1 answer:

ehidna [41]2 years ago

3 0

subtract 2x from both sides... 6x=2 divide by 6 = .3

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$y^{-1}(x)=\sqrt[3]{2-x}$

Just to verify:

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But in case you're actually only interested in computing the square root, first we note that $\sqrt x$ (the real-valued square root) is only defined as long as $x\ge0$ . So $\sqrt{-x^3}$ is defined as long as $-x^3\ge0$ , or $x^3\le0$ , or equivalently $x\le0$ . Under this condition, we could write

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We can simplify this further, but we have to be careful. Suppose $x=-1$ . Then $x^2=(-1)^2=1$ . But we get the same result if $x=1$ , since $x^2=1^2=1$ . There are two possible values of $x$ that given the same value of $x^2$ , so to capture both of them, we take $\sqrt{x^2}=|x|$ , the absolute value of $x$ . Then