length times width times height
(1¼) (4) (2)
= 10 cm3
Answer:

Step-by-step explanation:
we know that
The inscribed angle is half that of the arc comprising
so
![m\angle y=\frac{1}{2}[96^o]](https://tex.z-dn.net/?f=m%5Cangle%20y%3D%5Cfrac%7B1%7D%7B2%7D%5B96%5Eo%5D)

A=πr²
pool=π(y-4)²=π(y²-8y+16)
total=π(y+4)²=π(y²+8y+16)
walkway=total-pool
walkway=π(y²+8y+16)-π(y²-8y+16)=
π(y²+8y+16-y²+8y-16)=
π(16y)=
16πy
first option is answer
Answer:
$3.97x + $10 < (or equal to) $25
Step-by-step explanation: