Answer:
1) Separate the aqueous layer from the organic layer using the separation funnel.
2) Treat the aqueous layer to obtain compound A.
3) Distilated the organic layer to obtain compound B.
Explanation:
When <u>NaOH is added</u> to the mixture the acid groups will react to produce a salt and increases the polarity of the compounds due to the net charges generated. (Figure 1).
Therefore, the salt produced by compound A will move to the <u>aqueosus layer</u>. Compound B dont react due to the lack of <u>acid groups</u>. So, this molecule will stay in the <u>organic layer</u>.
When the aqueous layer is separated from the organic layer using the separation funnel we will have a <u>separation</u>. The compound will remain in the aqueous layer and compound b will remain in the organic layer.
Then we aqueous layer can be <u>treated with HCl</u> in order to obtain the initial A molecule, in other words: Undo the ionic form of compound A.
The organic layer can be removed by <u>distillation</u> in order to obtain the pure form of compound B.
Maybe 47.999 g if I can’t I’m sorry.
Its electronic confuguration is 2.8.6 so it occupies 3 shells.
Answer:
1) the product may be contaminated by the solvent
2) side reactions may yield unwanted products
3) some reactants may be present in the product if the reaction was incomplete
Explanation:
It is common in chemistry to pass reaction products through purification processes. This is done for a number of reasons.
First of all, some solvents molecules may be attached to the reaction product. These solvent particles must be separated in order to obtain a pure product.
Secondly, some side reactions also yield products that are isolated along with the desired products and these must be separated accordingly.
Finally, some chemical reactions do not go on to completion. This implies that some reactants may still be isolated alongside the product at the end of the reaction.
Answer:umm I think it’s B
Explanation:
