Answer: True
Explanation: I got done taking a science quiz and it had this question on it
The formula for the monoprotic acid is taken as HA, reaction with base is as follows;
HA + NaOH ---> NaA + H₂O
Stoichiometry of acid to base is 1:1
At the neutralisation point, number of HA moles = number of base moles
Number of NaOH moles reacted = 0.100M / 1000 mL /L x 30.0 mL = 0.003 mol
Therefore number of HA moles reacted = 0.003 mol
the mass of acid 0.384 g
Therefore molar mass - 0.384 g/ 0.003 mol = 128 g/mol
Answer:
There are 77 millimoles of nitric acid present in 35.0 mL of a 2.20 M solution
Explanation:
Molarity of the solution = 2.20 M

Therefore, there are 77 millimoles of nitric acid present in 35.0 mL of a 2.20 M solution
The state of atoms in a neon light when light is emitted is loss of energy.
I believe the answer is: in order not to write very big or very small number values