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Igoryamba
3 years ago
14

♦HURRY PLEASE!!! ♦ ↓ Don't worry about the answer choice that is highlighted : )

Mathematics
1 answer:
tatiyna3 years ago
4 0

Answer:

It's 3

Step-by-step explanation:

Bc it's placed before and it's multiplying the variable in the algebraic expression

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Write the nth term of the following sequence in terms of the first term of the sequence.
ZanzabumX [31]

Answer:

a(n) = 1 + 7(n-1)

Step-by-step explanation:

6 0
3 years ago
Use the expression 3n + 5p + 2 + n=??
dusya [7]
Terms: 3n, 5p, 2, n
Like Terms: 3n, n
Coefficients: 3, 5, 1
Constants: 2
Simplified Expression: 4n + 5p + 2
5 0
3 years ago
A) Work out the size of angle x. b) Give reason for your answer.
enot [183]

A

x=75°

B

We know that ∠EFG=∠ABF because they are corresponding angles.

We also know that ∠x+∠ABF=180, because angles along a straight line always equal 180:

x+105=180

x=75°

6 0
3 years ago
Two competitive neighbours build rectangular pools that cover the same area but are different shapes. Pool A has a width of (x +
GenaCL600 [577]

<u>Answer: </u>

a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

b) Area of pool A is equal to area of pool B equal to 24.44 meters.

<u> Solution: </u>

Let’s first calculate area of pool A .

Given that width of the pool A = (x+3)  

Length of the pool A is 3 meter longer than its width.

So length of pool A = (x+3) + 3 =(x + 6)

Area of rectangle = length x width

So area of pool A =(x+6) (x+3)        ------(1)

Let’s calculate area of pool B

Given that length of pool B is double of width of pool A.

So length of pool B = 2(x+3) =(2x + 6) m

Width of pool B is 4 meter shorter than its length,

So width of pool B = (2x +6 ) – 4 = 2x + 2

Area of rectangle = length x width

So area of pool B =(2x+6)(2x+2)        ------(2)

Since area of pool A is equal to area of pool B, so from equation (1) and (2)

(x+6) (x+3) =(2x+6) (2x+2)    

On solving above equation for x    

(x+6) (x+3) =2(x+3) (2x+2)  

x+6 = 4x + 4    

x-4x = 4 – 6

x = \frac{2}{3}

Dimension of pool A

Length = x+6 = (\frac{2}{3}) +6 = 6.667m

Width = x +3 = (\frac{2}{3}) +3 = 3.667m

Dimension of pool B

Length = 2x +6 = 2(\frac{2}{3}) + 6 = \frac{22}{3} = 7.333m

Width = 2x + 2 = 2(\frac{2}{3}) + 2 = \frac{10}{3} = 3.333m

Verifying the area:

Area of pool A = (\frac{20}{3}) x (\frac{11}{3}) = \frac{220}{9} = 24.44 meter

Area of pool B = (\frac{22}{3}) x (\frac{10}{3}) = \frac{220}{9} = 24.44 meter

Summarizing the results:

(a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

(b)Area of pool A is equal to Area of pool B equal to 24.44 meters.

5 0
3 years ago
Please help.<br> A<br> B<br> C<br> D
s344n2d4d5 [400]

Answer:

A. t(x) = 450 - 0.06x

Step-by-step explanation:

The layer which is originally 450 m thick is decreasing by 0.06 m.

450 - 0.06

... per day. x represents days.

0.06x

So,

450 - 0.06x

6 0
3 years ago
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