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s344n2d4d5 [400]
2 years ago
14

Which equation can be used to find one or more factors of 26?

Mathematics
1 answer:
ratelena [41]2 years ago
8 0

Last one
26x2=52
!!!!!!!!!!!!!!!!!!!!
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In solving a rate of increase problem,the original value is always the?
PilotLPTM [1.2K]
<span>In solving a rate of increase problem,the original value is always the percent of new value. Hope this answers the question. Have a nice day. Feel free to ask more questions. Thank you.</span>
3 0
3 years ago
Each deck has 52 cards in it. Using m, write an expression for the total number of cards.
n200080 [17]

Answer: 52m cards

Step-by-step explanation:

First part of question says: Karen has m decks of cards.

If Karen has m deck of cards and each deck has 52 cards in it, the total number of cards that all that Karen will have will be 52 multiplied by the number of deck of cards Karen has:

= 52 * m

= 52m

5 0
2 years ago
Please help what is the area?
ratelena [41]

Answer: 70 square units

6 0
3 years ago
Find the indicated probability or percentage for the sampling error. The distribution of weekly salaries at a large company is r
Flauer [41]

Answer:

The probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

Step-by-step explanation:

According to the Central Limit Theorem if we have a non-normal population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample means is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

\mu=\$1000\\\sigma=\$370\\n=80

As <em>n</em> = 80 > 30, the central limit theorem can be used to approximate the sampling distribution of sample mean weekly salaries.

Let \bar X represent the sample mean weekly salaries.

The distribution of \bar X is: \bar X\sim N(\$1000,\ \$41.37)

Now we need to compute the probability of the sampling error made in estimating the mean weekly salary to be at most $75.

The sampling error is the the difference between the estimated value of the parameter and the actual value of the parameter, i.e. in this case the sampling error is, |\bar X-\mu|= 75.

Compute the probability as follows:

P(-75

                                     =P(-1.81

Thus, the probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

3 0
3 years ago
Find the mean of the following data set.<br><br> 42, 45, 58, 63
MakcuM [25]
The mean is 52 because 42+45+58+63=208 then you divide it by the amount of numbers: 4 : 208 divided by 4= 52
8 0
2 years ago
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