The equation is L = 34 – 0.5d for the water level, L, after d days
<h3><u>Solution:
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Given that , Suppose that the water level of a river is 34 feet
And that it is receding at a rate of 0.5 foot per day.
We have to write an equation for the water level, L, after d days
The equation can be framed for water level after d days which is found by calculating difference between initial level and receding level of water per day
Now , we know that,
<em>water level after d days = initial level – receded level of water.
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L = 34 feet – number of days spent x rate of receding level per day.
L = 34 feet – d days x 0.5 foot
L = 34 – 0.5d
Hence, the equation is L = 34 – 0.5d
Answer: 720
Step-by-step explanation: Hope this helps
5(b-3c)
Divide the entire polynomial by 5, as that is the only factor that is common throughout the entire polynomial.
First, illustrate the problem into a diagram like the one shown in the attached picture. The component vectors are shown in red (y-component) and blue (x-component). Since this is a right triangle, let's apply the trigonometric functions of sine and cos.
y-component, vy:
sin (π/3) = vy/8
vy = 6.928x-component, vx:
cos (π/3) = vx/8
vx = 4
9514 1404 393
Answer:
252.8 cm²
Step-by-step explanation:
The missing side of the right triangle can be found from the Pythagorean theorem:
s² = 20² -16² = 400 -256 = 144
s = 12 . . . . cm
The area of a right triangle is more easily found using the traditional area formula:
A = 1/2bh
A = 1/2(12 cm)(16 cm) = 96 cm² (left-side triangle)
The area of the triangle on the right can be found from Heron's formula. The semiperimeter is ...
s = (16 +20 +23)/2 = 29.5
The area is ...
A = √(29.5(29.5 -16)(29.5 -20)(29.5 -23)) = √(29.5·13.5·9.5·6.5)
A = √24591.9375 ≈ 156.818 . . . . . cm² (right-side triangle)
Then the total area of the figure is ...
A = 96 cm² +156.818 cm² = 252.818 cm² . . . . total area