Answer:
1410
Step by step explanation:
<em>2</em><em>/</em><em>5</em><em>x</em><em>=</em><em>5</em><em>6</em><em>4</em>
<em>5</em><em>/</em><em>2</em><em>*</em><em>2</em><em>/</em><em>5</em><em>x</em><em>=</em><em>5</em><em>6</em><em>4</em><em>*</em><em>5</em><em>/</em><em>2</em>
<em>x</em><em>=</em><em>1</em><em>4</em><em>1</em><em>0</em>
<em>Proof</em><em>:</em><em> </em><em>2</em><em>/</em><em>5</em><em>*</em><em>1</em><em>4</em><em>1</em><em>0</em><em>=</em><em>5</em><em>6</em><em>4</em>
Hope it helps <3
Multiples of 30 : 30,60,90,120,150....
and the first one that 4 goes into evenly is 60
Answer: 0.02
Step-by-step explanation:
OpenStudy (judygreeneyes):
Hi - If you are working on this kind of problem, you probably know the formula for the probability of a union of two events. Let's call working part time Event A, and let's call working 5 days a week Event B. Let's look at the information we are given. We are told that 14 people work part time, so that is P(A) = 14/100 - 0.14 . We are told that 80 employees work 5 days a week, so P(B) = 80/100 = .80 . We are given the union (there are 92 employees who work either one or the other), which is the union, P(A U B) = 92/100 = .92 .. The question is asking for the probability of someone working both part time and fll time, which is the intersection of events A and B, or P(A and B). If you recall the formula for the probability of the union, it is
P(A U B) = P(A) +P(B) - P(A and B).
The problem has given us each of these pieces except the intersection, so we can solve for it,
If you plug in P(A U B) = 0.92 and P(A) = 0.14, and P(B) = 0.80, you can solve for P(A and B), which will give you the answer.
I hope this helps you.
Credit: https://questioncove.com/updates/5734d282e4b06d54e1496ac8
