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lutik1710 [3]
3 years ago
8

Victoria’s printer can print 8.804 in one minute if Victoria’s prints page for 0.903 minutes, about how many pages will she have

.
Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
8 0

Victoria’s printer can print 8.804 in one minute if Victoria’s prints page for 0.903 minutes,

We apply unitary method

In one minute the number of pages printed is 8.804. we need to find the number of pages for 0.903 minutes

1 minute = 8.804 pages

0.903 minutes = ? pages

We multiply 8.804 by 0.903

8.804 * 0.903 = 7.95

Number of pages printed = 7.95 pages


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What are the 10th and 90th percentiles of the distribution of sample proportion for the population proportion below?
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Answer:

The 10th percentile is 0.0784.

The 90th percentile is 0.1616.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

For a proportion p in a sample of size n, we have that \mu = p, \sigma = \sqrt{\frac{p(1-p)}{n}}

In this problem, we have that:

\mu = 0.12, \sigma = \sqrt{\frac{0.12*0.88}{100}} = 0.0325

10th percentile:

X when Z has a pvalue of 0.1. So X when Z = -1.28.

Z = \frac{X - \mu}{\sigma}

-1.28 = \frac{X - 0.12}{0.0325}

X - 0.12 = -1.28*0.0325

X = 0.0784

The 10th percentile is 0.0784.

90th percentile:

X when Z has a pvalue of 0.9. So X when Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 0.12}{0.0325}

X - 0.12 = 1.28*0.0325

X = 0.1616

The 90th percentile is 0.1616.

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