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photoshop1234 [79]
3 years ago
8

5x+18/8 = x/4 Solve for x

Mathematics
1 answer:
ollegr [7]3 years ago
8 0

Answer: x= -9/19

Step-by-step explanation:

5x+18/8=x/4

5x+ 9/4=x/4

5x+9/4-9/4=x/4-9/4

5x= x-9/4

5x(4)=x-9/4(4)

20x=x-9

20x-x=x-9-x

19x=-9

19x/19=-9/19

x=-9/19

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Sum and simplify 7/8+3/8
n200080 [17]
7/8+3/8=10/8
10/8=5/4
The answer as an improper fraction is 5/4 and 1 and 1/4 as a mixed fraction.

Hope I didn't mess up for your sake.

5 0
4 years ago
Read 2 more answers
Does anyone know the answer to this?
PolarNik [594]

Answer:

(B) The exponents should be subtracted by the quotient rule of exponents

Step-by-step explanation:

Let's examine how this was solved.

(\frac{4^2 4^3}{4^{-5}})^2

He first rose everything in the parentheses to the second power, which is just multiplying all the exponents by 2. This is correct.

\frac{4^4 4^6}{4^{-10}}

He then combined the numerator exponents. Exponent rules say that a^b \cdot a^c = a^b+c, so he should have ended up with 4^{10}, which he did. This is correct.

\frac{4^{10}}{4^{-10}}

Now, what he did in the final step is wrong. He added the exponents. However, exponent rules tell us that when we have \frac{a^b}{a^c}, it equals a^{b-c}.

10 - (-10) = 10+10 = 20

So the final answer should have been 4^{20}

Hope this helped!

6 0
4 years ago
The contents of a cell in a spreadsheet are shown below. 4.7893541EE-6 What number does the contents of the cell represent?
matrenka [14]

Answer:

D

Step-by-step explanation:

6 0
4 years ago
Determine whether 25a^2 − 49b^6 is a difference of two squares. If so, factor it. If not, explain why.
My name is Ann [436]
It is the difference of 2 squares as its of the form a^2 - b^2

A is the correct answer.
7 0
3 years ago
Which of the following expression expressions is equivalent to cos3x/sinxcosx?
77julia77 [94]
Correct Option:
Option B

Solution:
The given expression is:

\frac{cos(3x)}{sin(x)cos(x)}

cos(3x) can be written as cos(2x +x). Expanding it, we get:

cos(3x) = cos(2x+x) \\  \\ 
cos(3x) =cos(2x)sin(x)-sin(2x)cos(x)

Using this value of cos(3x) in given equation, we get:

\frac{cos(3x)}{sin(x)cos(x)} \\  \\ 
= \frac{cos(2x)sin(x)-sin(2x)cos(x)}{sin(x)cos(x)} \\  \\ 
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=sec(x)cos(2x)-csc(x)sin(2x)
8 0
3 years ago
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