Answer:
Step-by-step explanation:
Given that;
Compressed Soil 2.85 2.66 3 2.82 2.76 2.81 2.78 3.08 2.94 2.86 3.08 2.82 2.78 2.98 3.00 2.78 2.96 2.90 3.18 3.16
Intermediate Soil 3.17 3.37 3.1 3.40 3.38 3.14 3.18 3.26 2.96 3.02 3.54 3.36 3.18 3.12 3.86 2.92 3.46 3.44 3.62 4.26
Compressed soil intermediate soil
Mean 2.907 3.286
SD 0.1414 0.2377
Here we have,

The pooled Standard deviation

So standard error for difference in population mean is

by inputting the values we get 0.0623
Degree of freedom for t is
df = 19 + 20 - 2 = 37,
so t-critical value is 2.715.
So required confidence interval for
will be


So required confidence interval is (0.2103 , 0.5483).
Let
x--------> the number
we know that
11²=121
12²=144
then
x² must be greater than 121 and less than 144
case a) <span>√115
if x=</span><span>√115
then
x</span>²=115-------> is not greater than 121
case b) <span>√121
</span>if x=√121
then
x²=121-------> is not greater than 121
case c) <span>√136
</span>if x=√136
then
x²=136-------> is greater than 121 and is less than 144------> is ok
case d) <span>√150
</span>if x=√150
then
x²=150------> is not less than 144
therefore
the answer is
√136
Answer:
5, 1, 5, 1.
Step-by-step explanation:
take it one step at a time.
for the first one f(g(1))
first do whats inside of the parenthesis.
> g(1), go to g(x) graph, go to x= 1 and your y-value is your new value (3)
> your new equation is now f(3)
→ go to f(x) graph, go to x= 3, your y-value is 5. Your final answer is 5.
Answer: y = (1/2)*x - 1
Step-by-step explanation:
a linear relationship is something like:
y = a*x + b, lets find the values of a and b.
We have that the output (y) must be 1 less than half of the imput (x), then our relation is:
y = (1/2)*x - 1