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Aleks [24]
3 years ago
6

Help me please i need help

Mathematics
1 answer:
Alisiya [41]3 years ago
3 0

Answer:

b

Step-by-step explanation:

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Solve for x Show your work
telo118 [61]

Answer:

x = 12

Step-by-step explanation:

To solve this and show your work, you have to start of with the equation (3x - 6) = 30.

You then have to add 6 to both sides like this:

(3x - 6) = 30 \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \: + 6  \:  \:  \:   \:  \:   + 6

So then the 6 is cancelled out, and you are left with

3x = 36.

Now you just have to divide both sides by 3 like this:

\frac{3x}{3}  =  \frac{36}{3}

Which cancels 3 out, and you are left with

x = 12.

4 0
3 years ago
A company makes 120 bags.
Nana76 [90]

Answer:

43 out of 120 have zips

Step-by-step explanation:

because

8 0
3 years ago
Read 2 more answers
Which of the following can be modeled with a linear function? Select all that apply.
kobusy [5.1K]

Answer:

Step-by-step explanation: ifk

3 0
3 years ago
50 points!!! Will mark brainliest if correct!! Pls help me!!
goldenfox [79]

Answer:

3rd option is correct, give me brainiest

4 0
3 years ago
Recall, we have five connectives in propositional logic ¬, ∧, ∨, →, ↔ (negation, conjunction, disjunction, conditional and bicon
Free_Kalibri [48]

Answer:

(a) ¬(p→¬q)

(b) ¬p→q

(c) ¬((p→q)→¬(q→p))

Step-by-step explanation

taking into account the truth table for the conditional connective:

<u>p | q | p→q </u>

T | T |   T    

T | F |   F    

F | T |   T    

F | F |   T    

(a) and (b) can be seen from truth tables:

for (a) <u>p∧q</u>:

<u>p | q | ¬q | p→¬q | ¬(p→¬q) | p∧q</u>

T | T |  F  |   F     |    T       |  T

T | F |  T  |  T      |    F       |  F

F | T |  F  |  T      |    F       |  F

F | F |  T  |  T      |    F       |  F

As they have the same truth table, they are equivalent.

In a similar manner, for (b) p∨q:

<u>p | q | ¬p | ¬p→q | p∨q</u>

T | T |  F  |   T     |    T    

T | F |  F  |   T     |    T    

F | T |  T  |   T     |    T    

F | F |  T  |   F     |    F    

again, the truth tables are the same.

For (c)p↔q, we have to remember that p ↔ q can be written as (p→q)∧(q→p). By replacing p with (p→q) and q with (q→p) in the answer for part (a) we can change the ∧ connector to an equivalent using ¬ and →. Doing this we get ¬((p→q)→¬(q→p))

4 0
3 years ago
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