Need help with this English assignment due now pls hurry up I need #10-13 poem help me out now
1 answer:
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let's keep in mind that, in the II Quadrant, cosine is negative and sine, is positive.
cosine is adjacent/hypotenuse, however the hypotenuse is simply a radius unit, and thus is never negative, so in the -(2/3) the negative must be the numerator, -2.
Answer:
Step-by-step explanation:
In this problem we have a horizontal ellipse, because the major axis is the x-axis
The equation of a horizontal ellipse is equal to
where
(h,k) is the center of the ellipse
a and b are the respective vertices distances from center
we have
vertices at (7, 0) and (-7, 0)
co-vertices at (0, 1) and (0, -1)
so
The center is the origin (0.0) (The center is the midpoint of the vertices)
a=7
b=1
substitute