From high temperature to low temperature.
Answer:
yesakskakakakakakkawbajajjakaak
The reaction for formation of water vapour is as follows ;
2H2+ O2 —> 2H2O
Water vapour is in the gaseous form, at STP , 1 mol of any gas occupies 22.4 L volume
If 22.4 L occupied by 1 mol
Then amount of moles in 436 L - 1/22.4 x 436= 19.5 mol
Stoichiometry of O2 to H2O is 1:2
Amount of O2 moles reacted to formed H2O is -19.5 mol /2 = 9.75 mol
In one experiment, you do not have the metal oxalate product
as dry as possible. This might affect the pyrolysis procedure by maybe the
water will react with the compound at very high temp; the initial weight of the
sample is already incorrect that might cause error in the further calculations.
A water molecule<span>, </span>because<span> of its shape, is a </span>polar molecule<span>. </span>