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mote1985 [20]
3 years ago
5

A box sits on a table. An arrow labeled F subscript N points up. An arrow labeled F subscript g points down. An arrow labeled F

subscript P points right. An arrow labeled A points left. The box is at rest on the table. Which force is represented by vector A? sliding friction rolling friction static friction fluid friction
Chemistry
1 answer:
Tresset [83]3 years ago
5 0

Answer:

Static Friction

Explanation:

You might be interested in
Starting with a vessel of temperature 50.1°C, a pressure of 6263.MmHg and volume 461.1mL, what is its final volume, in liters, i
il63 [147K]

Answer:

The value of final volume inside the vessel  V_{2} =  5.17 ml

Explanation:

Initial pressure P_{1} = 6263 mm Hg = 8.24 atm = 835 K pa

Initial temperature T_{1} = 50.1 ° c = 323.1 K

Initial volume V_{1} = 461.1 ml =  0.0004611 m^{3}

Final temperature T_{2} = - 95.8 ° c = 177.2 K

Finial pressure P_{2} = 411 atm = 41644.6 K PA

We know that

P_{1} \frac{V_{1} }{T_{1} }  = P_{2} \frac{V_{2} }{T_{2} }

Put all the values in the above equation

⇒ 835 × \frac{0.0004611}{323.1} = 41644.6 × \frac{V_{2} }{177.2}

⇒ V_{2} = 5.07 × 10^{-6} m^{3}

⇒ V_{2} =  5.17 ml

This is the value of final volume inside the vessel.

8 0
3 years ago
Pesticide concentrations in the Rhine River between Germany and France between 1969 and 1975 averaged 0.55 mg/L of hexachloroben
sertanlavr [38]

Answer:

1.93×10⁻³ mmoles/L of C₆Cl₆; 1.58×10⁻⁴ mmoles/L of C₁₂H₈Cl₆O; 3.51×10⁻³ mmoles/L of C₆H₆Cl₆

Explanation:

We have to find out the molar mass of each pesticide to calculate the moles, and then the milimoles

C₆Cl₆ → 12. 6 + 35.45 .6 = 284.7 g/m

C₁₂H₈Cl₆O →  12 . 12 + 8.1 + 35.45 .6 + 16 = 380.7 g/m

C₆H₆Cl₆ → 12.6 + 6.1 + 35.45 .6 = 290,7 g/m

Let's convert mg to g (/1000)

0.55 mg / 1000 = 5.5×10⁻⁴ g

0.060 mg / 1000 = 6×10⁻⁵ g

1.02 mg / 1000 = 1.02×10⁻³ g

Now we can know the moles (mass / molar mass)

5.5×10⁻⁴ g / 284.7 g/m = 1.93×10⁻⁶ moles of C₆Cl₆

6×10⁻⁵ g / 380.7 g/m = 1.58×10⁻⁷ moles of C₁₂H₈Cl₆O

1.02×10⁻³ g / 290,7 g/m = 3.51×10⁻⁶ moles of C₆H₆Cl₆

Milimoles = Mol . 1000

1.93×10⁻⁶ . 1000 = 1.93×10⁻³ mmoles of C₆Cl₆

1.58×10⁻⁷ . 1000 = 1.58×10⁻⁴ mmoles of C₁₂H₈Cl₆O

3.51×10⁻⁶ . 1000 = 3.51×10⁻³ mmoles of C₆H₆Cl₆

6 0
3 years ago
the value of kc for the following reaction is 0.630 at 409 K N2O4(g) --> 2NO2(g) if a reaction vessel at that temperature int
stealth61 [152]

<u>Answer:</u> The concentration of nitrogen dioxide at equilibrium is 0.063 M

<u>Explanation:</u>

We are given:

Initial concentration of nitrogen dioxide = 0.0250 M

Initial concentration of dinitrogen tetraoxide = 0.0250 M

For the given chemical equation:

                        N_2O_4(g)\rightleftharpoons 2NO_2(g)

<u>Initial:</u>                0.025        0.025

<u>At eqllm:</u>         0.025-x     0.025+2x

The expression of K_c for above equation follows:

K_c=\frac{[NO_2]^2}{[N_2O_4]}

We are given:

K_c=0.630

Putting values in above expression, we get:

0.630=\frac{(0.025+2x)^2}{(0.025-x)}\\\\x=-0.2013,0.019

Neglecting the negative value of 'x', because concentration cannot be negative

So, equilibrium concentration of nitrogen dioxide = (0.025 + 2x) = [0.025 + 2(0.019)] = 0.063 M

Hence, the concentration of nitrogen dioxide at equilibrium is 0.063 M

6 0
3 years ago
Which sound has waves with the greatest amplitude?'
Furkat [3]
Jet Takeoff because it is the loudest according to the chart by the number of decibels.
8 0
2 years ago
After the reaction between sodium borohydride and the ketone is complete, the reaction mixture is treated with water and H2SO4 t
In-s [12.5K]

Answer:

The hydrogen can be gotten from the added Acid or water during "workup".

Explanation:

Basically we can say that the reaction describe in this question is a Reduction reaction because of the chemical compound called sodium borohydride. In the reaction described above we can see that there is a Reduction of ketone to alcohol by the compound; sodium borohydride.

For the reduction Reaction to occur the C-O bond must break so as to enable the formation of O-H bond and C-H bond.

So, "the reaction mixture is treated with water and H2SO4 to produce the desired alcohol", thus, the oxygen will definitely pick up the hydrogen from H2SO4 or H2O.

7 0
3 years ago
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