14, 21
Step-by-step explanation:
Let the two consecutive multiples be 7n and 7(n+1).
Now, it is given that:
(7n)² + [7(n+1)]² = 637
Simplifying,
49n² + (7n+7)² = 637
49n² + 49n² + 2(7n)(7) + 49 = 637
(as (x+y)² = x² + y² + 2xy)
98n² + 98n + 49 = 637
98n² + 98n - 588 = 0
Dividing by 98 to further simplify,
n² + n - 6 = 0
Factorising, we get
n² + 3n - 2n - 6 = 0
n(n+3) - 2(n+3) = 0
(n+3)(n-2) = 0
Therefore we get n = -3 or n = +2.
Hence, we get the consecutive multiples as 14 and 21.
Feel free to ask if you didn't understand any part.
Hope this helps! :D
You have to add the 2 yards together... 5,215 + 1,850 = 7,065. If 2 bags will cover 2,500 square feet, then 1 bag will cover 1,250. Divide 7,065 by 1,250 and you will need 6 bags of seed. For problem 2, add all the purchases together, which will be $250.50. This will get him a 30% discount. So his total price after the discount will be about $175.35. For problem 3, this is an exponential function. The $10,000 loan with 9% rate over 5 years is equal to 10,000(1+0.09)^5 which is about $15,500, so he will have to pay an additional $5,500.
You have to flip the last fraction and multiple both the top by the top and the bottom by the bottom then you have to simply but just look that up or ask your teacher.
Cos θ=1/3
cos θ=sen (90-θ)
therfore:
sen (90-θ)=1/3
To chek
θ=arc cos 1/3=70.53º
sin (90-θ)=sin (90º-70.53º)=sin 19.47≈0.3333≈1/3
