How do I write 15 3/5% as a fraction

Mathematics

1 answer:

zaharov [31]3 years ago

3 0

I think the answer is 39/250

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10. Simplify the rational expression by rationalizing the denominator. 3 sqrt 160/sqrt 1350x A) 2 sqrt 15x/15x B) 3 sqrt 160/135

Viefleur [7K]

The simplified expression by rationalizing the denominator is (C) $\frac{4 \sqrt{15x} }{15x}$ .

First we must simplify the expression:
$\frac{3 \sqrt{160} }{\sqrt{1350x} } = \frac{12 \sqrt{10} }{15 \sqrt{6x} } = \frac{4 \sqrt{10} }{5 \sqrt{6x} }$

Then we factor the rational parts and cancel it out:
$\frac{4 \sqrt{2} \sqrt{5} }{5 \sqrt{2} \sqrt{3x} } = \frac{4\sqrt{5} }{5\sqrt{3x} }$

Then we rationalize the expression:
$\frac{4\sqrt{5} }{5\sqrt{3x} } * \frac{\sqrt{3x} }{\sqrt{3x} } = \frac{4 \sqrt{15x} }{5*3x} = \frac{4 \sqrt{15x} }{15x}$

<span>Finally, the simplified expression by rationalizing the denominator is (C) $\frac{4 \sqrt{15x} }{15x}$ .</span>

7 0

3 years ago

The figure shows two parallel lines KL and NO cut by the transversals KO and LN.

Sever21 [200]

Answer:

(A)

Step-by-step explanation:

From the given figure, we have to prove whether the two given triangles are congruent or similar.

Thus, From the figure, ∠3=∠4 (Vertically opposite angles)

Since, KL and NO are parallel lines and KO and LN are transversals, then

measure angle 1= measure angle 5 that is ∠1=∠5(Alternate angles).

Thus, by AA similarity rule, ΔKLM is similar to ΔONM.

Thus, Option A that is Triangle KLM is similar to triangle ONM because measure of angle 3 equals measure of angle 4 and measure of angle 1 equals measure of angle 5 is correct.

8 0

3 years ago

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What’s is the range of the function

jolli1 [7]

Answer:

Y <= 1

Step-by-step explanation:

This is because it is a solid line and a filled point on the top line, the bottom line is irrelevant for this question

3 0

3 years ago

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